Ask question

Ask question

All categories

8 months ago

14

C

1 answer:

Volgvan8 months ago

7 0

The arc angle AC is measured as 55 degrees.

<h3>How to find arc angle?</h3>

If two secant intersect in the exterior of a circle, then the measure of the angle formed is half the positive difference of the arcs intercepted.

Therefore, the secants intersect outside the circle at point E.

The arc angle AC can be found as follows:

Therefore,

m∠BED = 1 / 2 (arc angle AC - arc angle BD)

arc angle AC = x

arc angle BD = 23 degrees.

m∠BED = 16 degrees.

m∠BED = 1 / 2 (arc angle AC - arc angle BD)

16 = 1 / 2 (x - 23)

16 = 1 / 2x - 23 / 2

16 + 11.5 = 0.5x

27.5 = 0.5x

x = 27.5 / 0.5

x = 55 degrees.

Therefore,

arc angle AC = 55 degrees.

learn more on arc angle here: hhttps://brainly.com/question/23117081

#SPJ1

You might be interested in

Mr. Miller has a 20-foot ladder, which he

dimulka [17.4K]

Answer:

8 ft

Step-by-step explanation:

the ladder will make a right angle triangle with the house. The hypotenuse of the triangle is the ladder, 20 ft, and the height of the triagnle is 18 ft.

Solve for the base of the right angle triangle using pythagorean's theorem:

c=20, a=18, b=?

$b^{2}=c^{2} - a^{2}\\b^{2}=20^{2} - 18^{2}$

$b=\sqrt{72}$

$b= 8.49 ft$

round to the nearest foot,

b = 8 ft

3 0

2 years ago

Sarah bought a toaster for $105. this price was 1/4 its listed price. how much wasthe listed price?

trapecia [35]

$420
($105 x 4 = $420)

8 0

2 years ago

Divide 24 milliliters into the ratio of 6:2<br><br> What is the larger value?

Rashid [163]

Answer:

18 and 6

Step-by-step explanation:

Rn = 6 Ratio numerator

Rd = 2 Ratio Denominator

Rs = Rn + Rd

Rs = 6 + 2

Rs = 8

Ratio Sum

a = 24 Amount to Divide

M = a ÷ Rs

M = 24 ÷ 8

M = 3 Multiplier Ratio Division Calculation

Rr = Rn × M : Rd × M

Rr = 6 × 3 : 2 × 3

Rr = 18 : 6

4 0

2 years ago

Find the solutions of the quadratic equation 14x^2+9x+10=014x

Vesnalui [34]

Answer:

Option B. $x=-\frac{9}{28}(+/-)\frac{\sqrt{479}}{28}i$

Step-by-step explanation:

we know that

The formula to solve a quadratic equation of the form $ax^{2} +bx+c=0$ is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$14x^{2}+9x+10=0$

so

$a=14\\b=9\\c=10$

substitute in the formula

$x=\frac{-9(+/-)\sqrt{9^{2}-4(14)(10)}} {2(14)}$

$x=\frac{-9(+/-)\sqrt{-479}} {28}$

Remember that

$i=\sqrt{-1}$

substitute

$x=\frac{-9(+/-)\sqrt{479}i} {28}$

$x=-\frac{9}{28}(+/-)\frac{\sqrt{479}}{28}i$

5 0

2 years ago

Consider a series circuit consisting of a resistor of R ohms, an inductor of L henries, and variable voltage source of V(t) volt

ser-zykov [4K]

Answer:

$I(t)=\frac{1}{3}(1-e^{-30t})$

Step-by-step explanation:

We are given that

$\frac{dI}{dt}+\frac{R}{L}I=\frac{V(t)}{L}$

R=150 ohm

L=5 H

V(t)=10 V

$P=\frac{R}{L}=\frac{150}{5}=30$

$I.F=e^{\int Pdt}=e^{\int 30 dt}=e^{30 t}$

$I(t)\times I.F=\int e^{30 t}\times 10 dt+C$

$I(t)\times e^{30 t}=\frac{10}{30}e^{30 t}+C$

$I(t)=\frac{1}{3}+Ce^{-30 t}$

I(0)=0

Substitute t=0

$0=\frac{1}{3}+C$

$C=-\frac{1}{3}$

Substitute the values

$I(t)=\frac{1}{3}-\frac{1}{3}e^{-30 t}$

$I(t)=\frac{1}{3}(1-e^{-30t})$

5 0

2 years ago