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3 years ago

How to write 15 409 in word form

1 answer:

7 0

We have to write 15,409 in word form.
15,409 = 1 * 10,000 + 5 * 1,000 + 4 * 100 + 0 * 10 + 9 * 1
Answer:
The number is: fifteen thousand four hundred and nine.

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What is the code of this math puzzle (amount of Miles)

Marta_Voda [28]

Just work with it as seperate triangles and then add them up.

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3 years ago

Wayne spends 1/6th of an hour walking his dog. How much time does Wayne spend walking his dog in a week? *

Mila [183]

Answer:

10 minutes

Step-by-step explanation:

This is somewhat of a trick question and also incomplete.

Assuming he walks his dog 1/6th of an hour each week, he walks his dog 10 minutes per week.

If this is incorrect please tell me the complete question

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3 years ago

Of the 50 people who started a math class meeting at 10:00 each morning, only 37 finished the class. What fraction of people fin

saveliy_v [14]

Answer:

37/50

Step-by-step explanation:

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3 years ago

Write the resultant of the two vectors as an ordered pair. –6 5 and 6 –5

RideAnS [48]

Answer:

Resultant vector of two vectors is (0, 0).

Step-by-step explanation:

in this question two vectors having ordered pair (-6, 5) and (6, -5) have been given.

We can represent these vectors in the form of

$\vec{A}=-6\hat{x}+5\hat{y}$

and $\vec{A'}=6\hat{x}+(-5)\hat{y}$

Now the resultant of these vectors will be = A + A'

A + A' = $\vec{A}=-6\hat{x}+5\hat{y}$ + $\vec{A'}=6\hat{x}+(-5)\hat{y}$

So the resultant vector = (0 + 0)

Therefore the resultant will be (0, 0)

8 0

3 years ago

Read 2 more answers

1 pt) find the average rate of change of the function over the given intervals. h(t)=\cot (t);

blondinia [14]

$\text{Consider the function}\\
\\
h(t)=\cot(t) \text{ on the interval }\left [ \frac{\pi}{4}, \ \frac{3\pi}{4} \right ]\\
\\
\text{we know that the average rate of change of a funtion f(x) over the }\\
\text{interval [a, b] is given by}\\
\\
f_{avg}=\frac{f(b)-f(a)}{b-a}\\
\\
\text{so using this, the average rate of change of the given function is}$

$h_{avg}=\frac{h\left ( \frac{3\pi}{4} \right )-h\left ( \frac{\pi}{4} \right )}{\frac{3\pi}{4}-\frac{\pi}{4}}\\
\\
=\frac{\cot \left ( \frac{3\pi}{4} \right )-\cot \left ( \frac{\pi}{4} \right )}{\frac{3\pi-\pi}{4}}\\
\\
=\frac{(-1)-(1)}{\frac{2\pi}{4}}\\
\\
=\frac{-2}{\frac{\pi}{2}}\\
\\
\text{Average rate of change of function}=\frac{-4}{\pi}$

6 0

3 years ago