All categories

3 years ago

A) What fraction of a day is 8 hours?

Mathematics

1 answer:

Scrat [10]3 years ago

3 0

Answer:

a. 8/24 or 1/3 a day

b. 45/60 or 3/4 a hour

c. 1/7 of a week

d. 4/12 or 1/3 a year

Step-by-step explanation:

Simply divide by the conversion you want to set.

60 seconds is 1 hour

24 hours is 1 day

7 days is 1 week

3-4 weeks per month (depending on the month and year)

12 months a year

You might be interested in

The top of a round table is 4 feet in diameter. The top splits to allow two extra boards to be inserted. The expansion boards ar

Nutka1998 [239]

The answer will be 6

8 0

4 years ago

Solve the following system of linear equations by graphing:<br> 2x + 2y = 10<br> 8x + 8y = 24

andriy [413]

Answer:

Step-by-step explanation:

-8x - 8y = -20

8x + 8y = 24

0 ≠ 4

2y = -2x + 10

y = -x + 5

8y = -8x + 24

y = -x + 3

inconsistent

7 0

3 years ago

Write an equation in slope-intercept form (y = mx + b) , that perpendicular to y = 2x - 4 that passes through the point (3, - 3)

FromTheMoon [43]

Answer:

Step-by-step explanation:

perp. -1/2

y + 3 = -1/2(x - 3)

y + 6/2 = -1/2x + 3/2

y = -1/2x - 3/2

8 0

3 years ago

There is an ice cream & candy shop next door that is the

ella [17]

Answer:

it's the same side, so it'll be 15/30

5 0

3 years ago

An article presents a study of the failure pressures of roof panels. A sample of 15 panels constructed with 8-inch nail spacing

wariber [46]

Answer:

There is sufficient evidence to conclude that six inches spacing has a higher mean failure pressure than 8 inches

Reject $H_0\ at\ 5%$ level of significance

Step-by-step explanation:

From the question we are told that:

Sample size 1 $n_1=15$

Spacing 1 $s_1=8$

Mean 1 $\=x_1=8.48$

Standard deviation 1 $\sigma_1=0.96 kPa$

Sample size 2 $n_2=16$

Spacing 2 $s_2=6$

Mean 1 $\=x_1=9.93$

Standard deviation 1 $\sigma_1=1.02 kPa$

Generally the hypothesis is mathematically given as

Null $H_0:\mu_1-\mu_2$

Alternative $H_a:\mu_1\mu_2$

Generally the equation for pooled estimate is mathematically given by

$S=\sqrt{\frac{(n_1-1)\sigma_1^2+(n_2-1)\sigma_2^2}{n_1+n_2-2} }$

Therefore

$S=\sqrt{\frac{(15-1)0.96^2+(16-1)1.02^2}{15+15-2} }$

$S=0.9905$

Generally the equation for test statistics is mathematically given by

$t=\frac{\=x_1+\=x_2}{S\sqrt{\frac{1}{n _1}+\frac{1}{n_2}}}$

$t=\frac{\=8.48-9.93}{0.9905\sqrt{\frac{1}{15}+\frac{1}{15}}}$

$t=-4.00091$

Therefore From table

$P value=P(t_{15+15-2}=4.00091)$

$P value=0.00041918$

$P$

Therefore

There is sufficient evidence to conclude that six inches spacing has a higher mean failure pressure than 8 inches

Reject $H_0\ at\ 5%$ level of significance

3 0

3 years ago