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10 months ago

Kennedy’s car used 11 gallons to travel 319 miles. How many gallons of gas would she need to travel 406miles

1 answer:

5 0

In the US, the gallon is a unit of measurement for liquids like milk, fuel, and water. If the petrol in your automobile is nearly empty, you should stop and get at least a few more gallons. A gallon is equal to 4 quarts, or 3.785 liters, of liquid.

<h3>Explain about the gallons?</h3>

Eight pints make up a gallon, which is a unit of measurement for liquids. It is equivalent to roughly 4.546 liters in Britain. It is roughly equivalent to 3.785 liters in America.

A gallon of water in the US weighs 8.345 pounds or 3.785 kilogram at 17 degrees Celsius, while a gallon of water in the imperial system weighs 10.02 pounds or 4.545 kilogram. The Imperial gallon weighs 16.6% less than 1 US gallon (gal).

Gas consumption is affected by driving on hills and mountainous terrain, by the state of the roads (such as stop-and-go city traffic or highway travel), and by the weather (such as high winds or snow). We can safely infer that under a number of

Answer is 14 gallons of gas need to travel 406 miles

To learn more about gallons refer to:

brainly.com/question/26007201

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3 years ago

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Can some0ne help me?

PtichkaEL [24]

Answer:

(x - 2)/3

(x - 4)/-5 or (-x + 4)/5

Step-by-step explanation:

this is an inverse function, and to solve an inverse function you would :

swap x and g(x) without bringing the x coefficient with it, just simply swap the variables. Then, solve for g(x), and that's it

the first question's answer is :

g(x) = 3x + 2

x = 3(g(x)) + 2

x - 2 = 3(g(x))

(x - 2)/3 = g(x)

the second one is:

g(x) = 4 - 5x

x = 4 - 5(g(x))

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3 years ago

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F(x)=x^3+3

lawyer [7]

Answer:

(a) -3/4

(b) -0.75

Step-by-step explanation:

It's a bit hard to tell what constitutes an "iteration" when using the bisection method to approximate a polynomial root. For the purpose here, we'll say one iteration consists of ...

evaluating the function at the midpoint of the bracketing interval
choosing a smaller bracketing interval
identifying the x-value known to be closest to the solution

Thus, the result of the iteration consists of a bracketing interval and the choice of one of the interval's ends as the solution approximation.

(a) We observe that the graphs intersect in the interval (-1, 0). For the first iteration, we evaluate f(x)-g(x) at x=-1/2. This tells us the solution is in the interval (-1, -1/2). The x-value closest to the root is x=-1/2.

For the second iteration, we evaluate the function f(x)-g(x) at x=-3/4. This tells us the solution is in the interval (-1, -3/4). The x-value closest to the root is x=-3/4.

For the third iteration, we evaluate the function f(x)-g(x) at x=-7/8. This tells us the solution is in the interval (-7/8, -3/4). The x-value closest to the root is x=-3/4.

(b) The graph tells us the solution is approximately 0.7549. Rounded to 2 decimal places, the solution is approximately 0.75.

(c) The above solution found after 3 iterations rounded to 2 decimal places is exactly 0.75.

See the attached table for function values.

_____

<em>Comment on bisection iteration</em>

Since you cut the interval containing the root in half with each iteration, you gain approximately one decimal place for each 3 iterations. When the function value is very nearly zero at one of the interval endpoints, it can take many more iterations to achieve a better result.

Here, it takes 4 more iterations before an x-value becomes closer to the solution (x≈-97/128). And it takes one more iteration to move the end of the interval away from -3/4. After these 5 more iterations (8 total), the solution is known to lie in the interval (-97/128, -193/256). The corresponding solution approximation is -193/256. It is still only correct to 2 decimal places.