1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
grin007 [14]
3 years ago
8

Let x be a random variable representing the amount of sleep each adult in New York City got last night. Consider a sampling dist

ribution of sample means x. (a) As the sample size becomes increasingly large, what distribution does the x distribution approach? uniform distribution sampling distribution normal distribution binomial distribution (b) As the sample size becomes increasingly large, what value will the mean μx of the x distribution approach? μx μ μ/√n μ/n σ (c) What value will the standard deviation σx of the sampling distribution approach? σ/n σx σ/√n μ σ (d) How do the two x distributions for sample size n = 50 and n = 100 compare? (Select all that apply.) The standard deviations are μ / 50 and μ / 100, respectively. The means are the same. The standard deviations are the same. The standard deviations are σ / √50 and σ / √100, respectively. The standard deviations are μ / √50 and μ / √100, respectively. The standard deviations are σ / 50 and σ / 100, respectively.
Mathematics
2 answers:
Sonbull [250]3 years ago
8 0

Answer:

a) As the sample size becomes increasingly large, the distribution approximates a normal distribution.

b) As the sample size becomes increasingly large, the mean of the sampling distribution, μₓ, approach as the population mean, μ.

σₓ

c) The standard deviation of the sampling distribution is given as

σₓ = (σ/√n)

d) Two sampling distributions with Sample size 50 and 100 have standard deviation of sampling distribution of (σ/√50) and (σ/√100) respectively.

Step-by-step explanation:

The Central limit theorem explains that sample distributions obtained from a population distribution (especially normally distributed ones) have distributions that approximate a normal distribution, a mean that is equal to the population mean and a standard deviation of sampling distribution given as the population standard deviation divided by square root of sample size.

a) Just like the Central limit theorem explains, as the sample size becomes increasingly large, the distribution approximates a normal distribution

b) And as the sample size becomes increasingly large, the mean of the sampling distribution, μₓ, approach as the population mean, μ.

c) The standard deviation of the sampling distribution is given as the population standard deviation divided by square root of sample size.

d) Using the formula given in (c) above, the standard deviation of sampling distribution of two sampling distributions with sample size 50 and 100 are (σ/√50) and (σ/√100) respectively.

Hope this Helps!!!

dangina [55]3 years ago
4 0

Answer:

Step-by-step explanation:

Given that X is a random variable representing the amount of sleep each adult in New York City got last night.

a) Normal distribution (by central limit theorem)

b) Sample mean will approach population mean mu

c) the standard deviation σx of the sampling distribution approach to σ/√n

d)  The means are the same.

. The standard deviations are σ / √50 and σ / √100, respectively.

You might be interested in
Question D- If the area of a square is 121 square centimeters, what is its side length?
Ipatiy [6.2K]
The formula for the area of a square is the side squared, or multiplied together.

Basically, if the side length is x, the area is x*x or x^2.

We can use that to set up an equation.

x^2=121
x=square root of 121=11

Hope this helps!
3 0
3 years ago
Which set of side lengths form a right triangle?
vova2212 [387]

Answer:

 Answer is 7cm,8cm,10cm

Step-by-step explanation:

A^2+B^2=C^2

6 0
3 years ago
Read 2 more answers
Compute: 5 ∙ (2 + 3i)
dimulka [17.4K]

Answer:

It will be equal to 40

Step-by-step explanation:

We have to compute 5\times (2+3!)

Let first find 3 !

For this we have to use factorial concept

So 3! will be equal to 3! = 3×2×1 = 6

Now According to 6+2 = 8

And now after solving bracket we have to multiply with 5

So 5×8 = 40

So after computation 5\times (2+3!)=40

So the final answer will be 40

4 0
4 years ago
Please help with the steps as well!!
mariarad [96]

To solve this problem, we need to use the Pythagorean Theorem, which states that a^2 + b^2 must equal c^2. "a" is the length of one of the legs (shorter sides of the triangle) and "b" is the length of the other leg. "c" is the length of the hypotenuse.

a = y = 36.25cm

b = x = 20.93cm

a^2 + b^2 = c^2

(36.25)^2 + (20.93)^2 = c^2

1314.0625 + 438.0649 = c^2

√1752.1274 = √c^2

c = 41.8584209 ≈ 41.86

So your final answer is...

The length of the hypotenuse is about 41.86 cm.

4 0
3 years ago
Giventhat : APRQ ~AD<br> What is m
kow [346]

Answer:

∠D = 56°

∠D = 180° - (35° + 89°) = 56°

5 0
3 years ago
Other questions:
  • 311over500 as a decimal
    5·1 answer
  • The probability that an archer hits the target when it is windy is 0.4; when it is not windy, her probability of hitting the tar
    9·1 answer
  • (Will give brainliest) hey! I don’t know what to do here, could you tell me? Please add an explanation with your answers, I want
    13·1 answer
  • Which postulate or theorem proves that these two triangles are congruent?
    11·2 answers
  • 1. Tom distributed chocolates among his friends Alex and Kevin in the ratio 2: 1. If he had 12chocolates, how many did Kevin get
    8·1 answer
  • Emily is adding 51 and 29. Which steps can she use to add the numbers
    10·2 answers
  • What is the average rate of change over the interval [0, 4]?
    14·1 answer
  • Explain by step by step pls :( if u type something wrong ill report u
    15·1 answer
  • Ohh plz help me i really could use it
    7·1 answer
  • Mason is taking a multiple choice test with a total of 100 points available. Each question is worth exactly 5 points . What woul
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!