Question

What is the equation of the line that is perpendicular to y = 3x + 3 and passes through the point (−6, 9)?

Answer 1

The equation of the line will be equal to 3y = -x + 21.

A line may be defined as the straight figure drawn which has no end points. The equation of a line can be written in slope intercept form as y = mx + c where m is the slope of line, c is y intercept an x and y are independent and dependent variables. If a point (x₁, y₁) is given then equation of line is (y - y₁) = m (x - x₁). The slope of line which is perpendicular to a given line having slope m is equal to -1/m.

Now, equation of line is y = 3x + 3. If we compare with slope intercept form then, m = 3. Now, slope of line perpendicular to this line is equal to -1/3. Now, equation of line passing through point (-6, 9) is given as

(y - 9) = -1/3 (x + 6)

3y - 27 = -x - 6

=> 3y = -x + 21 which is the required equation of line.

Learn more about Slope intercept form at:

brainly.com/question/9317111

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