Answer:
Step-by-step explanation:
step a system of two equations c = child ticket a = adult ticket
eq 1) 2c + 1a = 8.2 multiply by 2
eq 2) 3c + 2a = 14.1
I will multiply eq 1 times TWO and subtract eq 2 from eq 1a)
eq 1a) 4c + 2a = 16.4
eq 2) 3c + 2a = 14.1
subtract (4c - 3c) + (2a -2a) = 16.4 - 14.1
c + 0 = 2.3 euros for one child ticket
Now find the adult ticket price, plug 2.3 for c into eq 1)
eq 1) 2c + 1a = 8.2
eq 1) 2(2.3) + 1a = 8.2 solve for a
4.6 + a = 8.2 substract 4.6 from both sides
a = 8.2 - 4.6
= 3.6 euros for one adult ticket
double check using eq 2) we know c and a values
eq 2) 3c + 2a = 14.1
eq 2) 3(2.3) + 2(3.6) = 14.1
6.9 + 7.2 = 14.1
14.1 = 14.1
He has a 26% of getting a strike, which means he has a 74% chance of not getting a strike ( 100% - 26% = 74%).
Multiply the chance of not getting a strike by the number of attempts:
0.74 x 0.74 x 0.74 x 0.74 x 0.74 = 0.22
The answer is B) 0.22
The probability of making a free throw is 77%, the probability of not making one would be 23% ( 100% - 77% = 23%).
Add the probability of making the first one ( 0.77) by the probability of making the second one multiplied by the probability of missing the second one ( 0.77x 0.23)
0.77 + (0.77 x 0.23)
0.77 + 0.18 = 0.95
The answer is D) 95%
7(x+2) = 35
Use the distributive property:
7x + 14 = 35
Subtract 14 from each side:
7x = 21
Divide both sides by 7:
x = 21 / 7
X = 3
The answer is C. 3
Given:
<span>11 11.5 10.5 17 14.5 14.5 18 17 19
Arrange in chronological order from least to greatest.
10.5 ; 11 ; 11.5 ; 14.5 ; 14.5 ; 17 ; 17 ; 18 ; 19
</span><span>I used an online lower and upper fence calculator to get the necessary data.
Minimum: 10.5
Maximum: 19
Q1: 11.25
Q2 or median: 14.5
Q3: 17.5
Interquartile range can be solved by subtracting the value of Q1 from the value of Q3
IQR = Q3 - Q1
IQR = 17.5 - 11.25
IQR = 6.25 CHOICE A. </span>
12.5 gallons..............
