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soldier1979 [14.2K]
3 years ago
7

An equation ___has one solution. alwa sometimes never

Mathematics
1 answer:
Kryger [21]3 years ago
5 0

Answer: Sometimes

Step-by-step explanation: An equation sometimes has one solution. There are some equations where their is no solution. An example of this would be x = x-1 There is no solution for this equation. There are also times when an equation has an infinite amount of solutions. An example is x=x no matter how many values you put in, all will be true.

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A school principal wants to know more about the number of students absent each day. He counts the number of students absent each
True [87]

Answer:

6.27

Step-by-step explanation:

We are to obtain the standard deviation of the given values :

{24, 18, 31,25, 34}

The standard deviation = √(Σ(x - mean)²/ n)

The mean = (ΣX) /n

Using calculator to save computation time :

The standard deviation, s = 6.27 (2 decimal places)

6 0
3 years ago
PLEASE I NEED THIS NOW 50 POINTS
4vir4ik [10]
25g = r , i think.

I would give an explanation but you seem in a hurry! Have a good day and good luck!
6 0
3 years ago
Need help with this data table need it to end up to 1024 thanks
Iteru [2.4K]
1 2 4 8 16 32 64 128 256 512 1024. each one is 2 times the previous

3 0
3 years ago
Solve: log (7t + 2) = 2<br>t =​
IrinaK [193]

Answer:

t = 14

Step-by-step explanation:

log (7t + 2) = 2

Raise each side to the power of 10

10 ^log (7t + 2) =10^ 2

7t+2 = 100

Subtract 2 from each side

7t+2-2 = 100-2

7t = 98

Divide each side by 7

7t/7 = 98/7

t = 14

7 0
3 years ago
Read 2 more answers
Determine the asymptotes of the function: y=x^3-5x^2+4x-25/x^2-4x+3
igomit [66]

Answer:

Vertical A @ x=3 and x=1

Horizontal A nowhere since degree on top is higher than degree on bottom

Slant A @ y=x-1  

Step-by-step explanation:

I'm going to look for vertical first:

I'm going to factor the bottom first:  (x-3)(x-1)

So we have possible vertical asymptotes at x=3 and at x=1

To check I'm going to see if (x-3) is a factor of the top by plugging in 3 and seeing if I receive 0 (If I receive 0 then x=3 gives me a hole)

3^3-5(3)^2+4(3)-25=-31 so it isn't a factor of the top so you have a vertical asymptote at x=3

Let's check x=1

1^3-5(1)^2+4(1)-25=-25 so we have a vertical asymptote at x=1 also

There is no horizontal asymptote because degree of top is bigger than degree of bottom

There is a slant asympote because the degree of top is one more than degree of bottom (We can find this by doing long division)

                       x   -1

                --------------------------------------------------

x^2-4x+3 |      x^3-5x^2+4x-25

                  - ( x^3-4x^2+3x)

                   --------------------------------

                            -x^2 +x  -25

                       -   (-x^2+4x-3)

                          ---------------------

                                   -3x-22

So the slant asymptote is to x-1

8 0
3 years ago
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