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gizmo_the_mogwai [7]
1 year ago
5

5^3^x + 14 = 78Solve the equations and check for extraneous solutions

Mathematics
1 answer:
alukav5142 [94]1 year ago
5 0

Answer:

hope it help! but only for x(

Step-by-step explanation:

x=0.86414612

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Fewer young people are driving. In 1983, 87% of 19-year-olds had a driver’s license. Twenty-five years later (in 2008) that perc
Dima020 [189]

Answer:

a) ME=1.96\sqrt{\frac{0.87 (1-0.87)}{1200}}=0.019  

b) ME=1.96\sqrt{\frac{0.75 (1-0.75)}{1200}}=0.0245  

c) On this case it's not the same since the proportion estimated for 1983 it's different from the proportion estimated for 2008. So since the margin of error depends of \hat p the margin of error change for part a and b.

Step-by-step explanation:

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

If solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

Part a

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical value would be given by:

z_{\alpha/2}=\pm 1.96

If we replace the values into equation (a) for 1983 we got:

ME=1.96\sqrt{\frac{0.87 (1-0.87)}{1200}}=0.019  

Part b

Since is the same confidence level the z value it's the same.  

If we replace the values into equation (a) for 2008 we got:

ME=1.96\sqrt{\frac{0.75 (1-0.75)}{1200}}=0.0245  

Is the margin of error the same in parts (a) and (b)? Why or why not?

On this case it's not the same since the proportion estimated for 1983 it's different from the proportion estimated for 2008. So since the margin of error depends of \hat p the margin of error change for part a and b.

3 0
3 years ago
Can you please help me solve each inequality and help me graph each solution set.. can u please help me with #5,#6,#7,#8
Law Incorporation [45]
5)  y ≥ -1/2
6)  x <span>< 3/4
7)  y </span>≥ 1/2
8) x <span>> 1</span>
7 0
3 years ago
How many meters are their in centimeter​
Zigmanuir [339]

Answer:

You mean how many centimerters are in a meter?

In that case 100.

Step-by-step explanation:

6 0
3 years ago
What is the rule for the nth term of the arithmatic sequence given below:
vaieri [72.5K]

Answer:

  an = 5/2 +3/2(n -1)

Step-by-step explanation:

The common difference is ...

  4 -5/2 = 3/2

The general rule is ...

  an = a1 +d(n -1)

For a1 = 5/2 and d = 3/2, the rule for this sequence is ...

  an = 5/2 +3/2(n -1)

___

This can be simplified to ...

  an = 1 +3/2n

5 0
2 years ago
Can someone plz meeee! :(
larisa [96]

Answer:

3.0 and 3.2

Step-by-step explanation:

they are going up by '.2'

5 0
3 years ago
Read 2 more answers
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