Y=mx+b, m=(y2-y1)/(x2-x1)

m=(7-4)/(6--3)=3/9=1/3

y=x/3 +b, now use either point to solve for b, I'll use (6,7)

7=6/3 +b

7=2+b

b=5 so our line is:

y=x/3 +5 or more neatly...

y=(x+15)/3

6 0

2 years ago

Read 2 more answers

Demarco substitutes a value for x in the equation 2x = 4.

MA_775_DIABLO [31]

Answer:

If both sides are equal

Step-by-step explanation:

If both sides are equal and are the same in both sides of the equation, than it is a solution.

For instance, the solution for 2x = 4, is x = 2 because 2(2) = 4 is 4 = 4.

6 0

2 years ago

What value of k will result in the quadratic having one rational solution if 4x2+kx+4=0?

PtichkaEL [24]

The value of 'k' in the quadratic Equation $4x^{2}+kx+4=0$ having one rational solution is k is 8.

<h3>What is a Quadratic Equation?</h3>

Quadratic equations are the polynomial equations of degree 2 in one variable of the type $f(x) = ax^{2} + bx + c = 0$ where a, b, c, ∈ R and a ≠ 0.
The standard form of a quadratic equation is $ax^{2} + bx + c = 0$ .