Answer:
10 hr
Step-by-step explanation:
i divided 990 by 90 and got 10 hr
Step-by-step explanation:
Let f(x)=y
y=2x/X-5
y(x-5)=2x
xy-5y=2x
x(y-2)=5y
x=5y/y-2
Apply x=5y/y-2, on f(x)
f(5y/y-2)=2(5y/y-2)/[(5y/y-2)-5]
=(10y/y-2)/[(5y-5y+10)/y-2]
=10y/10
=y
So f^-1(x)=5y/y-2
Answer:
24761 mosquitoes
5.4 days
Step-by-step explanation:
Let the equation that shows the population of the mosquitoes after x days,

Where,
P = Initial population,
r = rate of increasing per day,
Here, A = 1000, when x = 0,

A = 1900 when x = 1,

Thus, the required function that represents the population after x days,

If x = 4,
The number of mosquito after 4 days,

If A = 60,000,


Taking log both sides,


Thus, there will 60,000 mosquitoes after 5 days.
Answer:
x1 y1 x2 y2
3 -1 -8 0
ΔY 1
ΔX -11
slope= - 1/11
B= - 8/11
Step-by-step explanation:
Answer:
c
Step-by-step explanation:
i did it in a test and i used a calculator