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Mamont248 [21]
4 years ago
15

A business owner has just paid $6000 for a computer. It depreciates at a rate of 22% per year. How much will it be worth in 5 ye

ars.
Mathematics
1 answer:
katovenus [111]4 years ago
7 0

Answer:

It will be worth $1732.30.

Step-by-step explanation:

After 1 year : 6000 x .78 = 4680

2 yr - 4680 x .78 = 3650.4

3 yr - 3650.4 x .78 = 2847.312

4 yr - 2847.312 x .78 = 2220.90336

5 yr - 2220.90336 x .78 = 1732.304621

1732.30

I think this is what it was asking

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The answer to that will be the letter c , 24ft
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3 years ago
Whats the answer to the problem 62.8 / 3 = ?
Rainbow [258]
That is a direct division, if you are confused by the decimal point, lets get rid of it! We can get rid of the decimal point multiplying the upper and lower parts of the division by 10, lets do it:
<span>62.8 / 3
= 10*</span><span>62.8 / 10*3
= </span><span>628 / 30
we can try to reduce the fraction dividing by 2 the upper and lower parts:
= 314/15
and now we have to make the operation:
= 20.93</span>
3 0
4 years ago
Maggie's brother is 8 years younger than four times her age. The sum of their ages is 67. How old is Maggie?
Nat2105 [25]
M + b = 67
b = 4m - 8

m + 4m - 8 = 67
5m - 8 = 67
5m = 67 + 8
5m = 75
m = 75/5
m = 15 <=== Maggie's age

b = 4m - 8
b = 4(15) - 8
b = 60 - 8
b = 52.....her brother is 52
3 0
3 years ago
I have dyscalculia and I hate math. I am absolutely confused about multi step equations with fractions.
Galina-37 [17]

Answer:

If you have *dyslexia, then how do you know how to spell so well?

Step-by-step explanation:

7 0
2 years ago
The International Air Transport Association surveys business travelers to develop quality ratings for transatlantic gateway airp
motikmotik

Answer:

The 95% confidence interval for the population mean rating is (5.73, 6.95).

Step-by-step explanation:

We start by calculating the mean and standard deviation of the sample:

M=\dfrac{1}{n}\sum_{i=1}^n\,x_i\\\\\\M=\dfrac{1}{50}(6+4+6+. . .+6)\\\\\\M=\dfrac{317}{50}\\\\\\M=6.34\\\\\\s=\sqrt{\dfrac{1}{n-1}\sum_{i=1}^n\,(x_i-M)^2}\\\\\\s=\sqrt{\dfrac{1}{49}((6-6.34)^2+(4-6.34)^2+(6-6.34)^2+. . . +(6-6.34)^2)}\\\\\\s=\sqrt{\dfrac{229.22}{49}}\\\\\\s=\sqrt{4.68}=2.16\\\\\\

We have to calculate a 95% confidence interval for the mean.

The population standard deviation is not known, so we have to estimate it from the sample standard deviation and use a t-students distribution to calculate the critical value.

The sample mean is M=6.34.

The sample size is N=50.

When σ is not known, s divided by the square root of N is used as an estimate of σM:

s_M=\dfrac{s}{\sqrt{N}}=\dfrac{2.16}{\sqrt{50}}=\dfrac{2.16}{7.071}=0.305

The degrees of freedom for this sample size are:

df=n-1=50-1=49

The t-value for a 95% confidence interval and 49 degrees of freedom is t=2.01.

The margin of error (MOE) can be calculated as:

MOE=t\cdot s_M=2.01 \cdot 0.305=0.61

Then, the lower and upper bounds of the confidence interval are:

LL=M-t \cdot s_M = 6.34-0.61=5.73\\\\UL=M+t \cdot s_M = 6.34+0.61=6.95

The 95% confidence interval for the mean is (5.73, 6.95).

4 0
4 years ago
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