How do you graph this?

PLEASE PLEASE PLEASE HELP!!!!!

Sveta_85 [38]

I believe it would be a SAS

4 0

3 years ago

What is the cosecant of angle X?

givi [52]

Answer:

cscX = $\frac{y}{x}$

Step-by-step explanation:

using the trigonometric identity

cscX = $\frac{1}{sinX}$

sinX = $\frac{opposite}{adjacent}$ = $\frac{x}{y}$

cscX = $\frac{1}{\frac{x}{y} }$ = $\frac{y}{x}$

8 0

3 years ago

A sample of 200 observations from the first population indicated that x1 is 170. A sample of 150 observations from the second po

igor_vitrenko [27]

Answer:

a) For this case the value of the significanceis $\alpha=0.05$ and $\alpha/2 =0.025$ , we need a value on the normal standard distribution thataccumulates 0.025 of the area on each tail and we got:

$z_{\alpha/2} =1.96$

If the calculated statistic $|z_{calc}| >1.96$ we can reject the null hypothesis at 5% of significance

b) Where $\hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{170+110}{200+150}=0.8$

c) $z=\frac{0.85-0.733}{\sqrt{0.8(1-0.8)(\frac{1}{200}+\frac{1}{150})}}=2.708$

d) Since the calculated value satisfy this condition 2.708>1.96 we have enough evidence at 5% of significance that we have a significant difference between the two proportions analyzed.

Step-by-step explanation:

Data given and notation

$X_{1}=170$ represent the number of people with the characteristic 1

$X_{2}=110$ represent the number of people with the characteristic 2

$n_{1}=200$ sample 1 selected

$n_{2}=150$ sample 2 selected

$p_{1}=\frac{170}{200}=0.85$ represent the proportion estimated for the sample 1

$p_{2}=\frac{110}{150}=0.733$ represent the proportion estimated for the sample 2

$\hat p$ represent the pooled estimate of p

z would represent the statistic (variable of interest)

$p_v$ represent the value for the test (variable of interest)

$\alpha=0.05$ significance level given

Concepts and formulas to use

We need to conduct a hypothesis in order to check if is there is a difference between the two proportions, the system of hypothesis would be:

Null hypothesis: $p_{1} = p_{2}$

Alternative hypothesis: $p_{1} \neq p_{2}$

We need to apply a z test to compare proportions, and the statistic is given by:

$z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}$ (1)

a.State the decision rule.

For this case the value of the significanceis $\alpha=0.05$ and $\alpha/2 =0.025$ , we need a value on the normal standard distribution thataccumulates 0.025 of the area on each tail and we got:

$z_{\alpha/2} =1.96$

If the calculated statistic $|z_{calc}| >1.96$ we can reject the null hypothesis at 5% of significance

b. Compute the pooled proportion.

Where $\hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{170+110}{200+150}=0.8$

c. Compute the value of the test statistic.

z-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

Replacing in formula (1) the values obtained we got this:

$z=\frac{0.85-0.733}{\sqrt{0.8(1-0.8)(\frac{1}{200}+\frac{1}{150})}}=2.708$

d. What is your decision regarding the null hypothesis?

Since the calculated value satisfy this condition 2.708>1.96 we have enough evidence at 5% of significance that we have a significant difference between the two proportions analyzed.

5 0

3 years ago

A rectangular prism with a volume of

Fudgin [204]

Answer:I believe the answer is 12 because it takes 4, 1/4 unit cube to make 1 cubic unit so to make 3 cubic units you need 12, 1/4 unit cubes if that makes any sense. :) Please make Brainliest if this helped.

5 0

2 years ago

Read 2 more answers

An airplane travels 2416 kilometers against the wind in 4 hours and 2896 kilometers with the wind in the same amount of time. Wh

oee [108]

Answer: the rate of the plane in still air is 664 km/h and the rate of the wind is 60 km/h

Step-by-step explanation:

Let x represent the rate of the plane in calm air.

Let y represent the rate of the wind.

An airplane travels 2416 kilometers against the wind in 4 hours. This means that the total speed with which the plane flew is (x - y) mph.

Distance = speed × time

Distance travelled by the plane while flying against the wind is

2416 = 4(x - y)

Dividing both sides of the equation by 4, it becomes

604 = x + y- - - - - - - - - - - 1

It flew 2896 kilometers with the wind in the same amount of time.. This means that the total speed with which the plane flew with the wind is (x + y) mph.

Distance travelled by the plane while flying with the wind is

2896 = 4(x + y)

Dividing both sides of the equation by 2, it becomes

724 = x + y- - - - - - - - - - - 2

Adding equation 1 to equation 2, it becomes

1328 = 2x

x = 1328/2

x = 664

Substituting x = 664 into equation 2, it becomes

724 = 664 + y

y = 724 - 664

y = 60

5 0

3 years ago