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worty [1.4K]
3 years ago
7

How do you graph this?

Mathematics
1 answer:
Gemiola [76]3 years ago
6 0

Answer:

You need more information to graaph this.

Step-by-step explanation:

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Which statement is correct regarding the measurements of the parallelogram?
Contact [7]

Answer:

The first one is correct

Step-by-step explanation:

You can multiply the base and perpendicular height to find the area.

8 0
3 years ago
Read 2 more answers
Find the angle that makes them supplementary.
Semmy [17]

Answer:

130,110,40,90,165

Step-by-step explanation:

supplementary angles add up to 180

so 180-50= 130

180-70=110

etc

7 0
3 years ago
tom and jane want to build a round swimming pool in their backyard that is 20 feet across . how many square feet will the pool b
natulia [17]
Tom and Jane r rich !
6 0
2 years ago
The owner of the Rancho Grande has 3,060 yd of fencing with which to enclose a rectangular piece of grazing land situated along
Pavel [41]

Answer:

1170450 yd^2

Step-by-step explanation:

The first thing is to calculate the necessary perimeter, which would be like this:

2 * a + b = 3060

if we solve for b, we are left with:

b = 3060-2 * a

Now for the area it would be:

A = a * b = a * (3060-2 * a )

A = 3060 * a -2 * a ^ 2

To maximize the area, we calculate the derivative with respect to "a":

dA / da = d [3060 * a -2 * a ^ 2

]/gives

dA / day = 3060 - 4 * a

If we equal 0:

0 = 3060 - 4 * a

4 * a = 3060

a = 3060/4

a = 765 and d

Therefore b:

b = 3060 - 2 * a = 3060 - 1530 = 1530

A = a * b

A = 765 * 1530

A = 1170450 and d ^ 2

3 0
3 years ago
I HAVE LIKE 2 MORE QUESTIONS, HELP ME PLZ!
Ne4ueva [31]

Given:

Base length of triangle = 10 units

Height of triangle = \sqrt{44} units

Length of hypotenuse of triangle = 12 units

To find:

Exact value of Cos A

Steps:

The cosine of any angle is equal to the length of the adjacent side by the length of the hypotenuse side.

So,

Cos A = \frac{adjacent}{hypotenuse}

Cos A = \frac{10}{12}

Cos A = 0.833

Therefore, the exact value of cos A is 0.833.

Happy to help :)

If u need any help, feel free to ask

5 0
3 years ago
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