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2 years ago

What are the coordinates of a point P(x, y)

Mathematics

1 answer:

Svetradugi [14.3K]2 years ago

7 0

$R_{x-axis}$ means $P(x,y) \longrightarrow P'(x,-y)$ .

$R_{y-axis}$ means $P(x,y) \longrightarrow P'(x,-y)$

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A cylinder shaped container has a radius of 30 cm and a height of 100 cm. A glass sphere with a redius of 12 cm is placed inside

Artemon [7]

Vcylinder-Vsphere=water

Vcylinder=hpir^2
Vsphere=(4/3)pir^3

given

cylinderradius=30 and h=100
Vcylinder=100pi30^2=100pi900=90000pi
let's leave it in terms of pi for more exactness

sphereradius=12
Vsphere=(4/3)pi12^3=2304pi

cylinder-sphere=90000pi-2304pi=87696pi
using pi=3.14
water=275365.44 cubic cm

last option is corrrect

4 0

3 years ago

The Mountain View ski resort kept track of the number of visitors they had each weekend during their busy season. This box plot

Dimas [21]

Answer:

40% i assume.if not correct then sorry-w-

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Lara has $1,425 in her bank account. Write and solve an equation to show how much money she started with if that amount reflects

bixtya [17]

1,425 = 114%
so
1,425 = 114% • x

1,425 × 100 ÷ 114 = x
x = 1250

hope this helps!

8 0

3 years ago

In the given figure PQ is a transversal intersecting lines AB and CD. Find the measures of angles x and y. Hence prove AB//CD.

tekilochka [14]

Explanation:

From the given figure ,

AB || CD

PQ is a transversal

Given angles are 50° and 130°

50° and x are linear pair

⇛ 50°+x = 180°

⇛ x = 180°-50°

⇛ x = 130°

Therefore, "x" = 130°

and

130° and y are vertically opposite angles which are equal.

⇛ "y" = 130°

Therefore, y = 130°

Additional comment:-

If two parallel lines Intersected by a transversal then
Corresponding angles are equal.
Vertically Opposite angles are equal.
The sum of two adjacent angles is equal to 180° then they are called Linear Pair.

3 0

2 years ago

Complete parts (a) through (c) below. (a) Determine the critical value(s) for a right-tailed test of a population mean at t

olga_2 [115]

Answer:

a) The critical value on this case would be $t_{crit}=1.325$

b) The critical value on this case would be $t_{crit}=-1.345$

c) The critical values on this case would be $t_{crit}=\pm 2.201$

Step-by-step explanation:

Part a

The system of hypothesis on this case would be:

Null hypothesis: $\mu \leq \mu_0$

Alternative hypothesis: $\mu > \mu_0$

Where $\mu_0$ is the value that we want to test.

In order to find the critical value we need to find first the degrees of freedom, on this case that is given df=20. Since its an upper tailed test we need to find a value a such that:

$P(t_{20}>a) = 0.1$

And we can use excel in order to find this value with this function: "=T.INV(0.9,20)". The 0.9 is because we have 0.9 of the area on the left tail and 0.1 on the right.

The critical value on this case would be $t_{crit}=1.325$

Part b

The system of hypothesis on this case would be:

Null hypothesis: $\mu \geq \mu_0$

Alternative hypothesis: $\mu < \mu_0$

Where $\mu_0$ is the value that we want to test.

In order to find the critical value we need to find first the degrees of freedom, given by:

$df=n-1=15-1=14$

Since its an lower tailed test we need to find b value a such that:

$P(t_{14}$

And we can use excel in order to find this value with this function: "=T.INV(0.1,14)". The 0.1 is because we have 0.1 of the area accumulated on the left of the distribution.

The critical value on this case would be $t_{crit}=-1.345$

Part c

The system of hypothesis on this case would be:

Null hypothesis: $\mu = \mu_0$