Answer:
dude use the order of operations the square root the thing
PLEASE MARK ME AS BRAINLIST
Answer:
The system has no solutions
Step-by-step explanation:
we have
-----> equation A
----> equation B
Isolate the variable y in the equation A
![5y=4x-5](https://tex.z-dn.net/?f=5y%3D4x-5)
![y=\frac{4}{5}x-1](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B4%7D%7B5%7Dx-1)
-----> equation A'
Isolate the variable y in equation B
![0.10y=0.08x+0.10](https://tex.z-dn.net/?f=0.10y%3D0.08x%2B0.10)
![y=\frac{0.08}{0.10}x+1](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B0.08%7D%7B0.10%7Dx%2B1)
------> equation B'
Compare the equations A' and B'
The lines have the same slope but different y-intercept
Are parallel lines
therefore
The system has no solutions
Answer:
(14a + 3, 21a + 4) = 1
Step-by-step explanation:
Step-by-step explanation:
To prove that the greatest common divisor of two numbers is 1, we use the Euclidean algorithm.
1. In this case, and applying the algorithm we would have:
(14a + 3, 21a + 4) = (14a + 3, 7a + 1) = (1, 7a + 1) = 1
2. Other way of proving this statement would be that we will need to find two integers x and y such that 1 = (14a + 3) x + (21a + 4) y
Let's make x = 3 and y = -2
![(14a+3)(3) + (21a+4)(-2)\\42a+9-42a-8\\1](https://tex.z-dn.net/?f=%2814a%2B3%29%283%29%20%2B%20%2821a%2B4%29%28-2%29%5C%5C42a%2B9-42a-8%5C%5C1)
Therefore, (14a + 3, 21a + 4) = 1
You need to do it more out so I can see everything
Answer:
A
Step-by-step explanation:
The cosine of a right triangle is the adjacent over the hypotenuse. If the cosine is -3/5 then it must be a right triangle with sides 3, 4, & 5 since this is a Pythagorean triple. This means the sin will be -4/5. We know its negative because the tangent is positive so this is the 3rd quadrant where both Sine and Cosine are negative.