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3 years ago

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What is 7 1/7 as an improper fraction

1 answer:

vova2212 [387]3 years ago

3 0

Let me explain this to you....

7 1/7...to turn this into an improper fraction, take ur whole number (7) and multiply it by ur denominator (7 x 7 = 49), then add ur numerator (1)....49 + 1 = 50....now put that over ur original denominator (7)....resulting in :
50/7. <== ur answer

In summary : (whole number x denominator + numerator) / original denominator.

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In Exercise, find the derivative of the function.<br> y = ln(3 + x2)

erastovalidia [21]

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Step-by-step explanation:

We know the property of derivative: $\dfrac{d}{dx}(\log (x))=\dfrac{1}{x}$

Given function : $y=\ln(3 + x^2)$

Differentiate both sides with respect to x , we get

$\dfrac{dy}{dx}=\dfrac{d}{dx}(\ln(3 + x^2))$

$\Rightarrow\ \dfrac{dy}{dx}=\dfrac{1}{3 + x^2}\cdot\dfrac{d}{dx}(3 + x^2)$ [By Chain rule]

$\Rightarrow\ \dfrac{dy}{dx}=\dfrac{1}{3 + x^2}\cdot(0+2x)$

[Since $\dfrac{d}{dx}(a)=0$ , where a is scalar and $\dfrac{d}{dx}(x^n)=n(x)^{n-1}$ ]

$\Rightarrow\ \dfrac{dy}{dx}=\dfrac{2x}{3 + x^2}$

Hence, the derivative of the given function is $\dfrac{2x}{3 + x^2}$ .

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