All categories

1 year ago

Rewrite 7^5/7 with a single positive exponent

Mathematics

1 answer:

vaieri [72.5K]1 year ago

8 0

Answer:

7^4

Step-by-step explanation:

to divide exponents we just subtract what the exponent is so we can write it like this

7^5/7^1= 7^5-1=7^4

Hopes this helps please mark brainliest

You might be interested in

Suppose a tennis player hits a ball over the net. The ball leaves his racket 0.5m above the ground. The equation h = -4.9t2 + 3.

garik1379 [7]

Whats the bloody question

5 0

3 years ago

X + y = 92 and y = 3x - 4

Advocard [28]

∑ Hey, eduardolozanosalgado ⊃

Answer:

x=24 , y=68

Step-by-step explanation:

Given:

$\mathrm{\begin{bmatrix}x+y=92\\ y=3x-4\end{bmatrix}}$

Solution:

Substitute: $\mathrm{y = 3x-4}$

$\begin{bmatrix}x+3x-4=92\end{bmatrix}$

Isolate x for 4x - 4= 92 : x = 24

Substitute : x = 24

$y=3\cdot \:24-4$

$y=64$

Hence, the solutions are : $x=24,\:y=68$

xcookiex12

8/19/2022

6 0

2 years ago

What is the difference? StartFraction 2 x 5 Over x squared minus 3 x EndFraction minus StartFraction 3 x 5 Over x cubed minus 9

Fiesta28 [93]

The expression which is equivalent to the difference of the given algebraic fraction is,

$\dfr\dfrac{(x+5)(x+2)}{x(x-3)(x+3)}$

<h3>What is the difference? </h3>

Difference is the mathematical operation in which the one number is subtract from another number.

To find the difference of two fraction numbers, we find the least common factor of denominator and write the all numbers as one fraction.

The given expression in the problem is,

$\dfrac{2x+5}{x^2-3x}-\dfrac{3x+5}{x^3-9x}-\dfrac{x+1}{x^2-9}$

Factorize the denominator of each term as,

$\dfrac{2x+5}{x(x-3)}-\dfrac{3x+5}{x(x-3)(x+3)}-\dfrac{x+1}{(x-3)(x+3)}$

Here, the least common factor of the denominators is x(x-3)(x+3), therefore, the expression can be written as,

$\dfrac{(x+3)(2x+5)-(3x+5)-(x)(x+1)}{x(x-3)(x+3)}\\\dfr\dfrac{2x^2+5x+6x+15-3x-5-x^2-x}{x(x-3)(x+3)}\\\dfr\dfrac{x^2+7x+10}{x(x-3)(x+3)}\\\dfr\dfrac{(x+5)(x+2)}{x(x-3)(x+3)}$