X=1.33
i rounded to the nearest hundred, for problems like this you can use photomath
The answer to the questions
Solve for x:
x/3 + 2/5 = -4
x/3 + 2/5 - 2/5 = -4 - 2/5
x/3 = -22/5
x/3 * 3 = -22/5 * 3
x = -66/5 or -13 1/5
This is a pythagorean theorem problem therefore a^2+b^2=c^2
a=8, b=?, c=10
8^2+b^2=10^2
64+b^2=100
100-64=56
square root of b^2=square root of 56
b=2 rad14
2 rad14 +4=
2 (rad14 + 1)= ANSWER
