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Softa [21]
11 months ago
10

1. what would the effect have been on the calculated formula weight ([9] above) of your unknown as compared to the true formula

weight if the solution had been blue green when you filtered your product? too high, too low, or unchanged? explain.
Mathematics
1 answer:
kramer11 months ago
3 0

If the solution is blue-green, this indicates that some copper is still present in the solution and that not all of it has precipitated. Expect it to be too low because you will have less mass.

With very few exceptions, all copper(I) (cuprous) compounds are diamagnetic and colorless. Cu2O, Cu2Cl2, and cuprous sulfide are a few of the significant commercial compounds of copper(I) (Cu2S).

The molar mass of the element copper is determined by looking at its average atomic mass, which is 63.55 AMU on the periodic table. Since it is also our molar mass, we will now put it in a different unit: grams over moles (63.55 gmol). That is copper's molar mass.

If the solution is blue-green, there is still copper in the solution and not all of it has precipitated. Because you will have less bulk, anticipate it to be too low.

To know more about copper, refer to this link:

brainly.com/question/1543891

#SPJ4

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defon
There are 8 yellow and 24 blue. Our ratio from yellow to blue is 8:24.
To simplify this, we need to see if we can divide 8 and 24 by a common factor.
8 and 24 can be divided by 8, so let's do that.
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Answer:

1) y=(-1/4)x+(11/4)

2) y=(4)x-33

3) y=(2/3)x-11/3

4) y=(5)x-2

5) y=(3)x-7

6) y=(-1/4)x+(6)

Step-by-step explanation:

1) y=mx+b  3=(-1/4)(-1)+b  b= 11/4

2) y=mx+b  -5=(4)(7)+b  b= -33

3) y=mx+b  -5=(2/3)(-2)+b  b= -11/3

4) y=mx+b  3=(5)(1)+b  b= -2

5) y=mx+b  -1=(-3)(-2)+b  b= -7

6) y=mx+b  7=(1/4)(4)+b  b= 6

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