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Softa [21]
1 year ago
10

1. what would the effect have been on the calculated formula weight ([9] above) of your unknown as compared to the true formula

weight if the solution had been blue green when you filtered your product? too high, too low, or unchanged? explain.
Mathematics
1 answer:
kramer1 year ago
3 0

If the solution is blue-green, this indicates that some copper is still present in the solution and that not all of it has precipitated. Expect it to be too low because you will have less mass.

With very few exceptions, all copper(I) (cuprous) compounds are diamagnetic and colorless. Cu2O, Cu2Cl2, and cuprous sulfide are a few of the significant commercial compounds of copper(I) (Cu2S).

The molar mass of the element copper is determined by looking at its average atomic mass, which is 63.55 AMU on the periodic table. Since it is also our molar mass, we will now put it in a different unit: grams over moles (63.55 gmol). That is copper's molar mass.

If the solution is blue-green, there is still copper in the solution and not all of it has precipitated. Because you will have less bulk, anticipate it to be too low.

To know more about copper, refer to this link:

brainly.com/question/1543891

#SPJ4

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the area of a parallelogram is 36x^6y^5. if the base of the parallelogram is 3xy^2,what is the height of the parallelogram ​asap
trapecia [35]

Answer:

h = 12x^5y^3

Step-by-step explanation:

The area of a parallelogram is found using A = b*h. Substitute the values given and solve for h.

A = b*h

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4 0
4 years ago
After studying the diagram shown, Michael makes the following conclusions:
inn [45]

Answer:

Therefore, Michael concludes option C)

C)(DA)^{2}=(DG)^{2}+(AG)^{2}

Step-by-step explanation:

Given:

1. DG = 3 and the area of square DEFG is 9.

2. AG = 4 and the area of square GHIA is 16.

3. DA = 5 and the area of square ABCD is 25.

So we have,

(DG)^{2}=3^{2}=9\\ \\(AG)^{2}=4^{2}=16\\\\(DA)^{2}=5^{2}=25\\

Now Add DG² and AG² we get

(DG)^{2}+(AG)^{2}=9+16=25=(DA)^{2}

Which is also called as  Pythagoras theorem i.e

(\textrm{Hypotenuse})^{2} = (\textrm{Shorter leg})^{2}+(\textrm{Longer leg})^{2}

Therefore, Michael concludes option C)

C)(DA)^{2}=(DG)^{2}+(AG)^{2}

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3 years ago
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kompoz [17]
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