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Anarel [89]
3 years ago
13

What is 60,845-2,926=?​

Mathematics
2 answers:
Alchen [17]3 years ago
6 0

Answer:

your answer is 57,919

Step-by-step explanation:

60,845-2,926=57,919

Korvikt [17]3 years ago
4 0

Answer:

57,919

Step-by-step explanation:

 60,845

- 2,926

=57,919

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An altitude is drawn from the vertex of an isosceles triangle, forming a right angle
Hatshy [7]

Answer:56.8 inches

Step-by-step explanation:

For perimeter we must find the lengths of the 2 diagonal sides of the triangle which are the same because it is isosceles.

the triangle is cut directly in half so both halves of the base are 17/2

17/2 = 8.5

solve through pythagoren theorum

altitude^2 + (half of base)^2 = (diagonal length)^2

18^2 + (8.5)^2 = (diagonal length)^2

324 + 72.25 = (diagonal length)^2

396.3 = (diagonal length)^2

\sqrt{396.3} = diagonal length

diagonal length = 19.9

diagonal length + diagonal length + base = perimeter

19.9 + 19.9 + 17 = perimeter

56.8 inches = perimeter

6 0
2 years ago
The area of a triangular block is 49 square inches. If the base of the triangle is twice the height, how long are the base and t
andrezito [222]
1) Formula: area = height * base / 2

2) Call x the height:

height = x

base = 2x

3) State the equation:

(x)(2x) = 49 in^2

4) Solve the equation:

2x^2 = 49 in^s

x^2 = (49/2) in^2

x = √(49/2) in

x = 7√2 / 2 in = 3.5 √2 in

5) Solution:

height = 3.5 √2 in and base = 7√2 in

6) Verification: area = (7√2 in) (3.5√2 in) = 49 in^2

Answer: height = 3.5√2 in and base = 7√2 in.
5 0
3 years ago
The number of students in the period 7 study hall at jins school is 4 times the number of students in Jin’s home room how many s
Vlada [557]
I think it's 64. Not positive, but pretty sure it is. 
4 0
3 years ago
Read 2 more answers
PLEASE HURRY, ZOOM IN TO SEE IT BETTER
zlopas [31]

Answer:

(2,7)

Step-by-step explanation:

You read it from the point were they intersect

6 0
3 years ago
Solve the following system of equations. 3x+4y=12
Lesechka [4]

Answer:

(0,3) is the solution set for given system.

Step-by-step explanation:

Given that:

3x+4y=12  ------- eq1

2x-3y= -9 ------- eq2

Multiplying eq1 with 2 and eq2 with 3 we get:

6x + 8y = 24 --------- eq1

6x - 9y = -27 -------- eq2

Subtracting eq2 from 1 we get:

17y = 51

Dividing both sides by 17 we get:

y = 3

Putting value of 3 in eq1 we get:

3x + 4(3) = 12

3x + 12 = 12

3x = 0

Dividing both sides by 3

x = 0

So the solution set will be: (0,3)

i hope it will help you.

6 0
3 years ago
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