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1 year ago

How many 1/5's are in 7 wholes?

Mathematics

1 answer:

marta [7]1 year ago

3 0

Answer

Answer = 35

There are 35 (1/5)'s in a whole 7.

Explanation

How many (1/5) can be found in 7

This can be interpreted as

7 ÷ (1/5)

$7\div\frac{1}{5}$

But it should be noted that to simplify expressions involving the division sign and fractions, we move forward by converting the division sign into multiplication sign and the fraction after the sign changes form into its reciprocal.

$7\div\frac{1}{5}=7\times\frac{5}{1}=7\times5=35$

Hope this Helps!!!

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Laurie says summer is 1 over 4 of the year. Maria says summer is 3 over 12 of the year. Who is correct? explain

nasty-shy [4]

Answer:

Step-by-ste

Oh, oh! This is such a tricky question...

Guess what!

Both of them are correct. Why?

Because if we simplify 3/12, we get 1/4th!

(How do you simplify?)

3/12 = 1/4

Because if we divide both "3" and "12" in 3/12 by 3, we get 1 instead of 3 and 4 instead of 12.

I hope you've got it! ;)

4 0

3 years ago

Read 2 more answers

Please help! I'm getting timed.

Molodets [167]

Hi there! The answer is A.

$t = 2(s + 2)$
To get a proper idea of the type of function this formula represents we work out the parenthesis.

Working out the parenthesis can for instance be done using rainbow technique.
$t = 2s + 4$

We can now see sinilarities between this function an the general function of a line in slope intercept form
$y = mx + n$

The function t therefore describes a line with slope 2 and y-intercept 4. Therefore the answer is A.

3 0

3 years ago

What are the ordered pairs of the

9966 [12]

Start by writing the system down, I will use $y$ to represent $f(x)$

$y=x^2-5x+3\wedge y=-3$

Substitute the fact that $y=-3$ into the first equation to get,

$-3=x^2-5x+3$

Simplify into a quadratic form ( $ax^2+bx+c=0$ ),

$x^2-5x+6=0$

Now you can use Vieta's rule which states that any quadratic equation can be written in the following form,

$x^2+x(m+n)+mn=0$

which then must factor into

$(x+m)(x+n)=0$

And the solutions will be $m,n$ .

Clearly for small coefficients like ours $5,6$ , this is very easy to figure out. To get 5 and 6 we simply say that $m=3, n=2$ .

This fits the definition as $5=3+2$ and $6=2\cdot3$ .

So as mentioned, solutions will equal to $m=3, n=2$ but these are just x-values in the solution pairs of a form $(x,y)$ .

To get y-values we must substitute 3 for x in the original equation and then also 2 for x in the original equation. Luckily we already know that substituting either of the two numbers yields a zero.

So the solution pairs are $(2,0)$ and $(3,0)$ .

Hope this helps :)

5 0

2 years ago

Math help its urgent. I'll mark brainliest!!!

Goshia [24]

It's been such a long time, but I think (1) should be the addition property since your adding 5 to both sides.

And (2) should be the multiplication property due to multiplying both sides by 2.

3 0

3 years ago

What is the perimeter of the quadrilateral shown below?

GarryVolchara [31]

The perimeter of a shape is the sum of the lengths of its sides.

So, to find the perimeter of this quadrilateral, all we have to do is add the side lengths and simplify.

(x² - 6) + (2x + 5) + (x² - 3x) + (4x² + 2x)

x² + x² + 4x² + (-3x) + 2x + 2x + (-6) + 5

6x² + (-3x) + 2x + 2x + (-6) + 5

6x² + x + (-6) + 5

6x² + x + (-1)

6x² + x - 1

So, the perimeter of the quadrilateral is the quantity (6x² + x - 1).

Hope this helps!

8 0

2 years ago