you'd use the pythagorean theorem.
a^2+b^2=c^2
a is the first leg, b is the second leg, and c is the third leg.
10^2+13^2=c^2
100+169=c^2
269=c^2
take the square root of both sides
16.4=c
16.4cm is your answer!
We can first add up the cards so we know how many we have in all:
16 + 16 + 18 = 50 cards
We can do this a little bit easier if we get the "16"-cards in one number total.
16 + 16 = 32

= 32 x 2 =

50 x 2

= 64 : 2 = 32 %
100
We did just divide the % of two types cards on 2, so we get the %-chance of 1 type card.
I am not quite sure, but I think that 32 % is the correct answer.
L(1, -4)=(xL, yL)→xL=1, yL=-4
M(3, -2)=(xM, yM)→xM=3, yM=-2
Slope of side LM: m LM = (yM-yL) / (xM-xL)
m LM = ( -2 - (-4) ) / (3-1)
m LM = ( -2+4) / (2)
m LM = (2) / (2)
m LM = 1
The quadrilateral is the rectangle KLMN
The oposite sides are: LM with NK, and KL with NK
In a rectangle the opposite sides are parallel, and parallel lines have the same slope, then:
Slope of side LM = m LM = 1 = m NK = Slope of side NK
Slope of side NK = m NK = 1
Slope of side KL = m KL = m MN = Slope of side MN
The sides KL and LM (consecutive sides) are perpendicular (form an angle of 90°), then the product of their slopes is equal to -1:
(m KL) (m LM) = -1
Replacing m LM = 1
(m KL) (1) = -1
m KL = -1 = m MN
Answer:
Slope of side LM =1
Slope of side NK =1
Slope of side KL = -1
Slope of side MN = -1
Answer:
B.
Step-by-step explanation:
We have been given that the trapezoid shown in the attachment has been enlarged by a scale of 1.5. We are asked to find the area of the enlarged trapezoid.
The area of the original trapezoid is 36 square inches.
Since each side of the trapezoid is enlarged 1.5 times, so the area of new trapezoid would be 2.25 times greater than area of original trapezoid.
The area would be 2.25 times greater because area is product of sum of lengths of parallel sides and height.



Therefore, the area of the enlarged trapezoid would be
and option B is the correct choice.