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earnstyle [38]
1 year ago
15

In the table below, y is a linear function ofwsуХ3 5 7Y5-3-11What is the value of y when x = 0?SELE

Mathematics
1 answer:
SpyIntel [72]1 year ago
7 0
Linear functions

We can observe in the table that when x goes from 3 to 5, y decreases

How much does y decrease?

it goes from 5 to -3, then it decreases

-3 -5 = -8

then, if y starts with 5 when x = 3, then when x = 5 its value will be

5 - 8 = -3

when x = 5 it is -3, then when x = 7

-3 - 8 = -11

We can say that every time x increases 2 unities, y decreases 8

How many times y decreases when x increase 1 unity?

it should decrease

-8/2 = -4

Then we can have more information

If x = 3, then y = 5

if x = 4, then y = 5-4 = 1

if x = 5, then y = 1-4=-3

if x = 6, then y = -3 - 4 = -7

if x = 7, then y = -7 - 4 = -11

We want to know what is the value of y with the previous x values,

when x = 2, x =1 and x = 0

if x = 2. then y = 9, because 9 - 4 = 5

if x = 1, then y = 13, because 13 - 4 = 9

if x = 0, then y = 17, because 17 - 4 = 13

<h2>Answer, when x = 0, then y = 17</h2>

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Free_Kalibri [48]

Answer:

1191.4 ; 34.5

Step-by-step explanation:

Given the data:

29; 37; 38; 40; 58; 67; 68; 69; 76; 86; 87; 95; 96; 96; 99; 106; 112; 127; 145; 150

The sample variance and standard deviation can be obtained thus :

Σ(X - m)² / (n - 1)

Where, m = mean of the sample

n = sample size

The standard deviation equals, sqrt(variance )

Using a calculator:

The variance, σ² ;

Mean = Σx / n = 1681 / 20 = 84.05

(x -m)^2

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22636.95 / 19

= 1191.4184 = 1191.42

Standard deviation = sqrt( Variance)

Standard deviation = sqrt(1191.4184)

Standard deviation = 34.516929 = 34.52

4 0
3 years ago
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Answer:

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Step-by-step explanation:

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