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3 years ago

Rewrite as a simplified fraction 1.5 <-- repeating=?

1 answer:

5 0

$1.5555...=1.\overline{5}=1.(5)\\\\x=1.5555...\ \ \ |multiply\ both\ sides\ by\ 10\\10x=15.5555...\\\\10x-x=15.5555...-1.5555...\\9x=14\ \ \ \ |divide\ both\ sides\ by\ 9\\\\x=\frac{14}{9}\\\\\boxed{x=1\frac{5}{9}}$

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PLZ I NEED URGENT HELP

Hunter-Best [27]

Answer:

Project 4 Score ; 41

Step-by-step explanation:

Assuming that Project 4's score is x;

( Project 1 + Project 2 + Project 3 + Project 4 ) / 4 ⇒ take to substituting the value of each Project, provided Project 4's score being x;

45 = 42 + 49 + 48 + x / 4 ⇒ combine like terms,

45 = ( 139 + x ) / 4 ⇒ let 4 be a common denominator among numerator terms,

45 = 139 / 4 + x / 4 ⇒ divide 139 over 4,

45 = 34.75 + x / 4 ⇒ subtract 34.75 from either side,

10.25 = x / 4 ⇒ Multiply either side by 4,

x = 41 = Score of Project 4,

Solution; Project 4 ⇒ 41

6 0

3 years ago

Factor completely : 6x^2 - 4x - 2

TiliK225 [7]

$6x^2-4x-2\\-----------------------\\-4x=-6x+2x\\---------------------\\6x^2-6x+2x-2=6x(x-1)+2(x-1)=\boxed{(x-1)(6x+2)}\\----------------------\\6x+2=2(3x+1)\\------------------------\\Answer:\boxed{2(x-1)(3x+1)}$

6 0

3 years ago

A calzone is divided into 24 equal pieces. Glenn and Ben each ate one eighth of the calzone on Thursday. The next day, Ben ate

7nadin3 [17]

Answer:

12 pieces

Step-by-step explanation:

Since on Thursday Glenn and Ben each ate an eight, then total they ate 2*1/8=2/8=¼

¼ of 24 pieces is equivalent to

¼*24=6 pieces

The number of pieces that remain would be 24-6=18 pieces

The one third of leftover ate rhe next day will be equivalent to

⅓ of 18

⅓*18=6 pieces

Remaining pieces next day will be 18-6=12 pieces

Therefore, only 12 pieces out of 24 original pieces remain the following day.

3 0

3 years ago

A door delivery florist wishes to estimate the proportion of people in his city that will purchase his flowers. Suppose the true

zloy xaker [14]

Answer:

The probability that the sample proportion will differ from the population proportion by greater than 0.03 is 0.009.

Step-by-step explanation:

According to the Central limit theorem, if from an unknown population large samples of sizes n > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

The mean of this sampling distribution of sample proportion is:

$\mu_{\hat p}=p$

The standard deviation of this sampling distribution of sample proportion is:

$\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}$

As the sample size is large, i.e. n = 492 > 30, the central limit theorem can be used to approximate the sampling distribution of sample proportion by the normal distribution.

The mean and standard deviation of the sampling distribution of sample proportion are:

$\mu_{\hat p}=p=0.07\\\\\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.07(1-0.07)}{492}}=0.012$

Compute the probability that the sample proportion will differ from the population proportion by greater than 0.03 as follows:

$P(|\hat p-p|>0.03)=P(|\frac{\hat p-p}{\sigma_{\hat p}}|>\frac{0.03}{0.012})$

$=P(|Z|>2.61)\\\\=1-P(|Z|\leq 2.61)\\\\=1-P(-2.61\leq Z\leq 2.61)\\\\=1-[P(Z\leq 2.61)-P(Z\leq -2.61)]\\\\=1-0.9955+0.0045\\\\=0.0090$

Thus, the probability that the sample proportion will differ from the population proportion by greater than 0.03 is 0.009.

5 0

3 years ago

Can you please tell me asp

Lera25 [3.4K]

Answer:

i think 8

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers