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1 year ago

Evaluate 4y - 5x + 10m y=2 x=3 m=5

Mathematics

2 answers:

ludmilkaskok [199]1 year ago

8 0

Answer:

Step-by-step explanation:

4(2)-5(3)+10(5)

8-15+50

-7+50

hopes this helps please mark brainliest

Helga [31]1 year ago

6 0

Answer:

17/54,x=3 m=5

Step-by-step explanation:

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Solve and show your work please!x+7=2(3x-4)

Brrunno [24]

x + 7 = 2(3x - 4) Remove the brackets

x + 7 = 2*3x - 4*2

x + 7 = 6x - 8 Subtract 7 from both sides.

x + 7 - 7 = 6x - 8 - 7

x = 6x - 15 Subtract 6x from both sides

x - 6x = - 15

-5x = - 15 Divide by -5

-5x/-5 = -15/-5

x = 3

6 0

3 years ago

suppose that you have 3000$ to invest. which investment yields the greater return over a 10 year period: 8.04% compounded daily

Ksenya-84 [330]

Answer: Option A: 8.04% compounded daily

<u>Step-by-step explanation:</u>

$A = P\bigg(1+\dfrac{r}{n}\bigg)^{nt}\qquad where\\\\\bullet A = \text{accrued amount (principal plus interest earned)}\\\bullet P = \text{principal (amount invested)}\\\bullet r = \text{rate (in decimal form)}\\\bullet n=\text{number of times compounded in one year}\\\bullet t=\text{time (number of years)}\\\\\\Option\ A:\\A = \text{unknown}\\P=3000\\r=8.04\%\rightarrow 0.0804\\n=\text{daily}\rightarrow 365\\t=10\\\\A=3000\bigg(1+\dfrac{0.0804}{365}\bigg)^{365\times 10}\\\\.\ =\$ 6,702.79$

$Option\ B:\\A = \text{unknown}\\P=3000\\r=8.1\%\rightarrow 0.081\\n=\text{quarterly}\rightarrow 4\\t=10\\\\A=3000\bigg(1+\dfrac{0.081}{4}\bigg)^{4\times 10}\\\\.\ =\$ 6,689.37$

Option A results in the greater amount of money.

7 0

4 years ago

This one I can’t figure out! It has fractions too..

viva [34]

Answer:

3x+ 5 1/3

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

2x - y = 5

goldfiish [28.3K]

Im pretty sure that the answer it is A. 7
because if you subtract 2 from 7 you get 5

6 0

3 years ago

Read 2 more answers

A sports store received a shipment of 150 footballs and basketballs. 20% were basketballs. How many footballs were in the shipme

RideAnS [48]

0.20(150) = 30 basketballs were in the shipment. Since the shipment presumably comprised only footballs and basketballs, the remainder of the shipment must consist of footballs.

150 - 30 = 120 footballs were in the shipment.

7 0

3 years ago