<span><span><span><span>−<span>2<span>(<span>q−22</span>)</span></span></span>+q</span>+12</span>>0</span>
Step 1: Simplify both sides of the inequality.<span><span><span>
−q</span>+56</span>>0</span>
Step 2: Subtract 56 from both sides.<span><span><span><span>
−q</span>+56</span>−56</span>><span>0−56</span></span><span><span>
−q</span>><span>−56</span></span>
Step 3: Divide both sides by -1.<span><span><span>
−q</span><span>−1</span></span>><span><span>−56</span><span>−1</span></span></span><span>
q<56</span>
Answer: q<56
We know that
applying the law of cosines
a² = b²+ c²<span> – 2*b*c*cos(A)
</span>
in this problem
a=?
b=20
c=9
A=90°
so
a² = b²+ c² – 2*b*c*cos(A)
but
cos (A)=0
a² = b²+ c²-----> 20²+9²----> a²=400+81----> a²=481-----> a=√481
a=21.93-----> a=22
the answer is
22
Answer:
<u></u>
Explanation:
The text and the model are garbled.
This is the question amended:
<em />
<em>Hyun Woo is riding a ferris wheel. H(t) models his height (in m) above the ground, t seconds after the ride starts. Here, t is entered in radians.</em>
<em>H(t) = -10 cos(2π/150 t)+10</em>
<em />
<em>When does Hyun Woo first reach a height of 16 m?</em>
<em />
<h2>Solution</h2>
<em />
When <em>Hyun Woo reaches a height of 16 m</em> the <em>model </em>states:
- <em>16 = -10 cos(2π/150 t)+10</em>
<em />
Then you must find the lowest positive value of t that is a solution of the equation.
Solve the equation:
- <em>16 = -10 cos(2π/150 t)+10</em>
- t = 52.86s ≈ 53 s ← answer
1) 1.403
2) 1.1
3) 1.078
4) 1.001
HOPE THIS HELPED :)
The answer is B I hope you get it.
