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insens350 [35]
2 years ago
5

Help with this too plzzzzzzz

Mathematics
1 answer:
olganol [36]2 years ago
4 0

3×6×-4

=-72

-5(5+5)

=-25-25

=-50

4×-4²+-4×-7

=4×16+-4×-7

=64+ 28

=92

4-4×-7

=4+28

=32

-9²+5×-2²

=81+20

101

-32×24/-2×-1

=-768/2

=-384

-8²×-6/-3×-4²

=64×-6/-3×-16

=-384/48

=-8

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Simplify each exponential expression using the properties of exponents and match it to the correct answer.
saveliy_v [14]

1) (2\times3^-2)^3 (5\times3^2)^2 / (3^-2)(5\times2)^2 = 2

2) (3^3) (4^0)^2 (3\times2)^-3 (2^2) = 1/2

3) (3^7\times4^7) (2\times5)^-3 (5)^2 / (12^7) (5^-1) (2^-4) = 2

4) (2.3)^-1 (2^0) / (2.3)^-1 = 1

<u>Step-by-step explanation</u>:

Step 1 :

(2\times3^-2)^3 (5\times3^2)^2 / (3^-2)(5\times2)^2

⇒ (2^3) (3^-6) (5^2) (3^4) / (3^-2) (10^2)

⇒ (2.2^2.5^2) (3^-6.3^4) / (3^-2) (10^2)

⇒ (2)(10^2) (3^-2) / (3^-2) (10^2)

⇒ 2

Step 2 :

(3^3) (4^0)^2 (3\times2)^-3 (2^2)

Any number with power 'zero' is 1.

⇒ (3^3) (1^2) (3^-3) (2^-3) (2^2)

⇒ (2^(-3+2))

⇒ 2^-1 = 1/2

Step 3 :

(3^7\times4^7) (2\times5)^-3 (5)^2 / (12^7) (5^-1) (2^-4)

⇒ (12^7) (2^-3) (5^-3) (5^2) / (12^7) (5^-1) (2^-4)

⇒ (12^7) (2^-3) (5^-3) (5^2) / (12^7) (5^-1) (2^-4)

⇒ (2^-3) (5^(-3+2)) / (5^-1) (2^-4)

⇒ (2^-3) (5^-1) / (5^-1) (2^-4)

⇒ 1 / (2^-1)

⇒ 2

Step 4 :

(2.3)^-1 (2^0) / (2.3)^-1

⇒ (2^0)

⇒ Any number with power 'zero' is 1

⇒ 1

8 0
3 years ago
Given the function rule f(x) = x^2 - 5x + 1, what is the output of f(-3)?
mojhsa [17]
 f(x) = x²<span> - 5x + 1

f(-3) = (-3)</span>² - 5(-3) + 1
<span>
f(-3) = 25


</span>--------------------------------------------------<span>
Answer: f(-3) = 25 (Answer C)
</span>--------------------------------------------------
4 0
4 years ago
A ferris wheel is 10 meters in diameter and boarded from a platform that is 5 meters above the ground. The six o'clock position
Murrr4er [49]

Answer:

The equation is:

f (t) = 4 + 5 (1 - cos (2pi t / 2))

Step-by-step explanation:

with the previous exercise we look for the equation for h = f (t)

So the data we have are

Wheel diameter = 10m (wheel radius = 5m)

1 wheel gets 1 revolution in 2 minutes.

the beginning of a entry will be related to that f (0) = 4

our wish is that f (z) get at least 4 with an amplitude of 5 (this value determines the radius of the wheel) for 2 minutes

with this the particle f (t) is transformed into

f (t) = 4 + 5 (1 - cos (2pi t / 2))

We know that the maximum value of cos in t will be 0, 1 -cos has minutes, the result will be as follows:

f (t) = 4 + 5 (1 - cos (2pi t / 2))

5 0
3 years ago
Find the GCD of 48,120
dexar [7]

Answer:

24 is the GCD of 48,120

plz mark me as brainliest

3 0
3 years ago
Read 2 more answers
Round 20045 to 4 significant figures.
tresset_1 [31]

Answer:

2005

Step-by-step explanation:

4 0
3 years ago
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