Here we are given the x intercepts at x=3 and x=9
So let us try to make quadratic equation for this using given information.
We have factors in the form (x-a)(x-b)
where a and b are x intercepts given to us.
So rewriting in factored form:
Now let us simplify it:
Let us find the vertex now,
For a quadratic equation of the form:
For x coordinate , we have the formula,
So using this formula for our equation,
So x = 6
Answer: The x-coordinate of the parabola's vertex is 6.
HOPE THIS HELPS!!!!!!!!!!!!!! :)
The general equation given is x^2 - 4x + y^2 = -3. Transform this to an equation of a circle of the form x^2 + y^2 = r^2.
Use completing the square method:
x^2 - 4x + 4 + y^2 = -3 + 4
(x - 2)^2 + y^2 = 1
the center of the circle is (2,0) and r = 1
To check if it intersects the y axis, find the value of the x-intercept.
Answer:
The given expression can't be expressed in polynomial form. Hence, it is not a polynomial.
Step-by-step explanation:
P(x,n) is a polynomial of nth degree if it is of the form,
P(x,n) = 
where n is a finite positive integer and n ∈ N
and '
's are fixed but otherwise arbitrary constants ∀ i = 0(1)n .
Now, the given expression is,
which doesn't fit in the above form. Hence, it is not a polynomial.
