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algol13
11 months ago
5

Pete's Convenience Store has a beginning inventory of 12 cans of soup at a cost of $.85 each. During the year, the store purchas

ed 4 at $.95, 6 at $1.05, 7 at $1.35, and 8 at $1.50. By the end of the year, 18 cans were sold. Calculate (A) the number of cans of soup ending inventory and (B) the cost of ending inventory under LIFO, FIFO, and weighted average. (Round your final answers to the nearest cent.)
Mathematics
1 answer:
Zepler [3.9K]11 months ago
5 0

A) The number of cans of soup in ending inventory is <u>19.</u>

B) The cost of the ending inventory under LIFO, FIFO, and the weighted average is as follows:

LIFO                                  $17.15

FIFO                                 $25.65

Weighted average          $21.47

<h3>What are the inventory methods?</h3>

The inventory methods include First-in, First-out (FIFO), Last-in, First-out (LIFO), Weighted Average, and Specific Identification.

FIFO assumes that the physical flow of goods during sales follows the chronological sequence of their acquisition.

LIFO assumes that the first goods acquired are the last to be sold.

The Weighted Average uses an average to determine the costs allocated to ending inventory and the cost of goods sold.

Specific Identification identifies the specific goods sold with their costs.

Description                 Units Unit Cost  Total

Beginning inventory     12     $0.85     $10.20

Purchases                      4     $0.95       $3.80

Purchases                      6     $1.05        $6.30

Purchases                      7     $1.35        $9.45

Purchases                     8     $1.50       $12.00

Total                            37                     $41.75

Sales                            18

Ending inventory        19 (37 - 18)

Average cost = $1.13 ($41.75/37)

<u>LIFO</u>:

Ending inventory = $17.15 ($10.20 + $3.80 + 3 x $1.05)

<u>FIFO</u>:

Ending inventory = $25.65 (4 x $1.05 + $9.45 + $12.00)

<u>Weighted Average</u>

Ending inventory = $21.47 (19 x $1.13)

Learn more about the inventory methods at brainly.com/question/25056275

#SPJ1

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A stadium has 55,000 seats. Seats sell for ​$28 in Section​ A, ​$16 in Section​ B, and ​$12 in Section C. The number of seats in
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A=number of seats in section A
B=number of seats in section B
C=number of seats in section C

We can suggest this system of equations:

A+B+C=55,000
A=B+C                                      ⇒A-B-C=0
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We solve this system of equations by Gauss Method.

1             1              1               55,000
1            -1            -1                         0
28         16           12          1,158,000 


1             1              1               55,000
0            -2             -2             -55,000                                    (R₂-R₁)
0           12             16           382,000                                    (28R₁-R₂) 


1            1                1              55,000
0           -2              -2             -55,000
0            0                4               52,000                                     (6R₂+R₃)

Therefore:

4C=52,000
C=52,000/4
C=13,000


-2B-2(13,000)=-55,000
-2B-26,000=-55,000
-2B=-55,000+26,000
-2B=-29,000
B=-29,000 / -2
B=14,500.

A + 14,500+13,000=55,000
A+27,500=55,000
A=55,000-27,500
A=27,500.

Answer: there are 27,500 seats in section A, 14,500 seats in section B and 13,000 seats in section C.
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Steve props a ladder against a wall of a building so that the he can get to the roof and
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Set each set of parentheses equal
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ANSWER: width= 6cm; length= 9cm

Hope this helps! :)
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