Anna has 100 quarters and jazmin has 100 dimes 100 dimes are equal to 10.00 and 100 quarters are equal to 25.00 Anna has more
A=number of seats in section A
B=number of seats in section B
C=number of seats in section C
We can suggest this system of equations:
A+B+C=55,000
A=B+C ⇒A-B-C=0
28A+16B+12C=1,158,000
We solve this system of equations by Gauss Method.
1 1 1 55,000
1 -1 -1 0
28 16 12 1,158,000
1 1 1 55,000
0 -2 -2 -55,000 (R₂-R₁)
0 12 16 382,000 (28R₁-R₂)
1 1 1 55,000
0 -2 -2 -55,000
0 0 4 52,000 (6R₂+R₃)
Therefore:
4C=52,000
C=52,000/4
C=13,000
-2B-2(13,000)=-55,000
-2B-26,000=-55,000
-2B=-55,000+26,000
-2B=-29,000
B=-29,000 / -2
B=14,500.
A + 14,500+13,000=55,000
A+27,500=55,000
A=55,000-27,500
A=27,500.
Answer: there are 27,500 seats in section A, 14,500 seats in section B and 13,000 seats in section C.
Answer:
30 ft
Step-by-step explanation:
you use 35x sin(60) because 35 is the hypotenuse and the angle is 60 degrees
Answer:
The first equation answer is 10
And the second one 6
Step-by-step explanation:
The first equation
2/5 x +3= 2/3x +1/3
2x + 15/5 = 6x+3/9 the cress cross
9(2x + 15) = 5(6x + 3)
18x + 135 = 30x +15
135-15 = 30x - 18x
120 = 12x
120/12 =12x/12
10 = x
X =10
The second one
-2.6b +4 =0.9b - 17
-2.6b - 0.9b = - 17 - 4
-2.6b + (-0.9b) = - 17 + (-4)
-3.5b = - 21
-3.5b/-3.5 = - 21 /-3.5
B= 6
W= width
l= length= 2w-3
Area= length * width
A= lw
substitute l=2w-3 for l
54= (2w-3)(w)
54= 2w^2 - 3w
subtract 54 from both sides
0= 2w^2 - 3w - 54
factor the polynomial
0= (2w + 9)(w - 6)
Set each set of parentheses equal
to 0 and solve for width.
0=2w+9
-9=2w
-4.5= w NEGATIVE VALUE
0=w-6
6 cm=w
-4.5 is not the answer because it has a negative value. You cannot have a negative side of a photograph. So substitute 6 in to find length.
length= 2w-3
l= 2(6)-3
l= 12-3
l= 9 cm
CHECK:
w= 6cm
l= 9cm
Area= length * width
54= 6*9
54= 54
ANSWER: width= 6cm; length= 9cm
Hope this helps! :)