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Genrish500 [490]
3 years ago
15

in 2004, 34.2 million accountants e-filed income tax returns. this was 114% of the number who e-filed in 2003.

Mathematics
1 answer:
ASHA 777 [7]3 years ago
4 0
Find one percent by dividing it by 100, then multiply it by 114 and you will have your answer cx
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2. At the local park, there is an annual fair that
mafiozo [28]

Answer:

132 children and 88 adults

Step-by-step explanation:

let x represent the amount of kids and y represent the amount of adults.

since the problem says there was a total of 220 people at the fair an equation can be made

x+y=220

the problem tells that each childrens ticket was 1.5$ and each adult ticket was $4 and that a total of $550 was made that day, we can use the knowledge to make an equation:

1.5x + 4y = 550

using the equations we can make this systems of equations:

1.5x + 4y =550

x + y =220

solve the systems of equations by subracting y on both sides of th bottom equation:

x=220-y

since x is equivant to 220-y it can be substitued for x in the first equation to make this:

1.5(220-y)+4y =550

--solve for y--

y=88  - there were 88 adults

substute 88 for y in the second equation

x+88=220

--solve for x--

x=138 - there were 132 children

7 0
2 years ago
What are the solutions to these graphed systems of equations?
olga2289 [7]

Answer:

A is (0,4) and B is no solution

Step-by-step explanation:

The lines both intercept at the point (0,4) on the graph while the lines in B won't ever intercept

3 0
2 years ago
3 + (-3)^2 - (9 +7)^0
MatroZZZ [7]

Answer:

11

Step-by-step explanation:

3+(−3)^2−(9+7)^0

=3+9−(9+7)^0

=12−(9+7)^0

=12−16^0

=12−1

=11

any number to the power of 0 is ALWAYS 1

3 0
3 years ago
Read 2 more answers
What is the sum to this equation ?pl
SVEN [57.7K]
The answer is 15/10.
5 0
3 years ago
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You have two exponential functions. One function has the formula g(x) = 5 x . The other function has the formula h(x) = 5-x . Wh
AVprozaik [17]
Given the exponential functions g(x)= 5^{x} and h(x)= 5^{-x}

k(x)=(g-h)(x)
k(x)=g(x)-h(x)

k(x)= 5^{x} - 5^{-x}
k(x)= 5^{x} - \frac{1}{ 5^{x} }
k(x)= \frac{ 5^{x} 5^{x}  }{ 5^{x} } - \frac{1}{ 5^{x} }
k(x)= \frac{ 5^{2x} }{ 5^{x} } - \frac{1}{ 5^{x} }
k(x)= \frac{ 5^{2x}-1 }{ 5^{x} }
4 0
3 years ago
Read 2 more answers
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