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SVEN [57.7K]
2 years ago
6

A football is kicked vertically upward from a height of 2 feet with an initial speed of 50 feet per second. The formula h=2+50t-

16t² describes the ball's height above the ground, h, in
feet, t seconds after it was kicked. Use this formula to find the ball's height 2 seconds after it was kicked.
The ball's height, 2 seconds after it was kicked, was feet.
Mathematics
1 answer:
Oksanka [162]2 years ago
5 0

Answer: 38 feet.

Step-by-step explanation:

The equation of motion of a body thrown vertically upwards:

                                       \displaystyle\\\boxed {h=h_0+v_0t-\frac{gt^2}{2} \ \ \ \ \ (1)},

h_0=2 \ feet\ \ \ \  v_0=50\  feet\  per\  second.

Substitute in formula (1) the value t=2 c:

h=2+50*2-16*2^2\\h=2+100-16*2*2\\h=102-64\\h=38\ feet.

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Angle K = Angle M
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KNL is congruent to MLK
4 0
3 years ago
find the domain of y equals 4 multiplied by the square root of the quantity 4 multiplied by x plus 2 end of quantity. a. x is gr
Bingel [31]
y=4\sqrt{4(x+2)}\\\\D:4(x+2)\geq 0\ \ \ |divide\ both\ sides\ by\ 4\\\\x+2\geq0\ \ \ |subtract\ 2\ from\ both\ sides\\\\\boxed{x\geq-2}\to\boxed{c.}
7 0
3 years ago
Given: p: x – 5 =10 q: 4x + 1 = 61 Which is the inverse of p → q? If x – 5 ≠ 10, then 4x + 1 ≠ 61. If 4x + 1 ≠ 61, then x – 5 ≠
AfilCa [17]
Answer: <span>If x – 5 ≠ 10, then 4x + 1 ≠ 61

Justification:
</span>
1) The inverse of a conditional is negating both the hipothesis and the conclusion of the conditional, keeping the same sense of the implication.

2) This is the scheme (the symbol ~ is used to negate)

conditional: p → q
hypothesis: p
conclusion: q

negated hypothesis: ~p
negated conclusion: ~ q

inverse conditional: ~p → ~q

3) So, for the hypotheis <span>p: x – 5 =10 and the conclusion q: 4x + 1 = 61, the conditional p→ q is:

 if x - 5 = 10 then 4x + 1 = 61.

And the inverse is negating both the x - 5 = 10 and 4x + 1 = 61, leading to:

If x – 5 ≠ 10, then 4x + 1 ≠ 61, which is the answer.</span>

8 0
4 years ago
I need help for the solution​
Sonja [21]

Answer:

\boxed{ \ dY_t=(2\theta+2\psi Y_t+\phi^2)dt+2\phi \sqrt{Y_t}dW_t\ }

Step-by-step explanation:

it is a long time I have not applied Ito's lemma

I would say the following

for f(x)=x^2

f'(x)=2x

f''(x)=2

so using Ito's lemma we can write that

dY_t=2V_tdV_t+\phi^2dt

dY_t=2(\theta+\psi V_t^2)dt+2\phi V_tdW_t+\phi^2dt

dY_t=(2\theta+2\psi V_t^2+\phi^2)dt+2\phi V_tdW_t

so it comes

dY_t=(2\theta+2\psi Y_t+\phi^2)dt+2\phi \sqrt{Y_t}dW_t

3 0
3 years ago
What type of number can be written as a fraction plq, where p and q are integers
Salsk061 [2.6K]

Answer:

rational number

Step-by-step explanation:

written as a fraction p/q, where p and q are integers and q is not equal to zero, is called as rational numbers. Example - 4/5, 2, 100, 1/7 etc all are rational numbers.

8 0
3 years ago
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