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kykrilka [37]
3 years ago
8

find the domain of y equals 4 multiplied by the square root of the quantity 4 multiplied by x plus 2 end of quantity. a. x is gr

eater than or equal to 1 divided by 2. b. x is greater than or equal to negative the quantity 1 divided by 2 end of quantity. c. x ≥ –2 d. x is greater than 1 divided by 2.
Mathematics
1 answer:
Bingel [31]3 years ago
7 0
y=4\sqrt{4(x+2)}\\\\D:4(x+2)\geq 0\ \ \ |divide\ both\ sides\ by\ 4\\\\x+2\geq0\ \ \ |subtract\ 2\ from\ both\ sides\\\\\boxed{x\geq-2}\to\boxed{c.}
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I need help and plez
Ksivusya [100]
100 / 120 / 121
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Hope this helps
3 0
3 years ago
Any suggestions or answers
Ahat [919]

Answer:

A=675cm²

Step-by-step explanation:

Area of triangle=1/2(base × height)

A=1/2(b × h)

A=1/2(6x × 9x)

where x=5

A=1/2(6×5×9×5)

A=1/2(30×45)

A=1/2(1350)

divide 1350 by 2

A=675cm²

7 0
3 years ago
What series of transformation takes Figure B to figure B PLEASE HELP ME!​
Sauron [17]

Answer:

translation

Step-by-step explanation:

right 7 down 9

3 0
3 years ago
What is the converse for this statement? Is the converse true?
nalin [4]
Yes I think your correct I don’t really understand the question ..
5 0
3 years ago
The first difference of a sequence is 1, 4, 7, 10, 13…
Rama09 [41]

Answer:

1) {4, 5, 9, 16, 26, 39}

2) {3, 4, 8, 15, 25, 38}

3) {3, 4, 8, 15, 25, 38}

Step-by-step explanation:

Hi!

Let's call the sequence {x₁, x₂, x₃, etc}

The information you have is the difference between to consecutive terms:

x_2-x_1= 1\\x_3-x_2= 4\\x_4-x_3= 7\\x_4-x_5= 10\\x_6-x_5= 13

1) Data: x₁=4, then to get x₂ you sum 1, and get x₂=5. Then to get x₃ you sum 4, and get x₃=9, and so on. Result:  {4, 5, 9, 16, 26, 39}

2) Data: x₁ + x₂ = 7. You know that x₂ = x₁ + 1. Then:

x_1+x_2 = x_1 +x_1 +1= 2x_1+1=7\\x_1=3\\x_2= x_1 +1 = 3+1=4

If you continue the same process as in 1), you get {3, 4, 8, 15, 25, 38}

3) Data: x₅ = 25. If you look at the result in 2), you see that x₅ = 25 there!

So the sequence in this case is the same as before {3, 4, 8, 15, 25, 38}

8 0
3 years ago
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