If you would like to solve the equation b^2 + 9 * b + 18 = 0 for the variable b, you can do this using the following step:
b^2 + 9 * b + 18 = 0
(b + 3) * (b + 6) = 0
Result:
1. solution: b = - 3
2. solution: b = - 6
Answer:
you kinda need to show a dot plot for someone to answer your question
Step-by-step explanation:
Answer:
A
Step-by-step explanation:
Since cosine is positive and sine is negative that puts θ in Quad IV.
From right triangles we know:
Cos θ = adjacent/hypotenuse = 5/13
sin θ = opposite/hypotenuse = ?/13
To find the opposite side across from θ use the pythagorean theorem.
5² + y² = 13²
25 + y² = 169
y² = 144
y = 12
we are given that sin is < 0 so sinθ = -12/13
Answer:
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Answer:
y^2 - 10y + 25
Step-by-step explanation:
(y - 5)^2 =
(y - 5) • (y - 5)
Multiply y times y
y^2
Add 5 and 5
10
Multiply 5 and 5
25
Add these terms together
y^2 - 10y + 25
