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Romashka [77]
1 year ago
10

The wavelength of ultraviolet light is about 0.00000003 inches. Which number best approximates this length as a power of 10?

Mathematics
1 answer:
Phantasy [73]1 year ago
4 0
Letter C is the answer
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The scale on a map indicates that 1 inch represents 10 miles. If two cities are 2 3 4 inches apart on a map, how many miles apar
Delicious77 [7]

Answer:

Step-by-step explanation:

2340 miles

Given

1 inch represents 10 miles

thus,

1 inch on map = 10 miles in real

given the two cities are 234 inches apart on map

1 inch on map = 10 miles in real

multiplying both side by 234

1 inch*234 on map = 10 miles*234 in real

234 inch on map = 2340 miles in real.

Thus, two cities are 2340 miles apart.

3 0
3 years ago
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Please help me :(( 35 POINTS!!!
4vir4ik [10]
-2(2x-1/2)/3 <= 1/5x-1
-2(2x-1/2)/3 <= x/5-1
-10(2x-1/2)<= 3x-15
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5<=3x-15+20
5<=23x-15
5+15<=23x
20<=23
20/23 <=x
x>=20/23
Decimal Form: 0.869565
4 0
3 years ago
In straight-line depreciation, if a car is purchased for $28,000 and is depreciated over 10 years, then what is the annual depre
Natasha2012 [34]
28,000÷10
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5 0
4 years ago
PLSSSSSSS HELPPPPPppppp
icang [17]

Answer:

20 units

Step-by-step explanation:

The polygon has 4 vertices as indicated by the 4 coordinate points given.

(3, 1) and (8, 1) is a horizontal side of length 8 - 3 = 5

Similarly

(3, 6) and (8, 6) is the opposite horizontal side of length 8 - 3 = 5

Points (3, 1) and (3, 6) is a vertical side of length 6 - 1 = 5

(8, 1) and (8, 6) is the opposite side of length 6 - 1 = 5

The polygon is therefore a square of side 5 units.

Perimeter = 4 × 5 = 20 units

5 0
3 years ago
Form quadratic equation with roots (alpha² + 1/alpha²) and (beta²+1/beta²)​
sashaice [31]

Answer:

What equation? Here’s a big tip for you, equations contain an ‘equals sign’ (‘=’) and something that they are equal to. I’m assuming your equation is:

ax2+bx+c=0  

I’m going to use  p  and  q  for the roots of the equation as they are easier to type than  α  and  β . Thus we have:

a(x−p)(z−q)=0⇒ax2−a(p+q)x+apq=0  

Equating coefficients with our initial equation:

x1 :  b=−a(p+q)⇒p+q=−ba  

x0 :  c=apq⇒pq=ca  

 

Now  p2+q2=p2+2pq+q2−2pq=(p+q)2−2pq  

=(−ba)2−2ca  

=b2a2−2ca  

=b2−2aca2

3 0
3 years ago
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