When the author observed a sobriety checkpoint conducted by the Dutchess County Sheriff Department, he saw that 676 drivers were
screened and 6 were arrested for dri vi ng while intoxicated. Based on those results, we can estimate that P(I) = 0.00589, where W denotes the event of screening a driver and getting someone who is intoxicated. What does P(I¯) denote, and what is its value?
The probability of drivers who are not intoxicated is P(I¯) and is given as 0.99411.
Step-by-step explanation:
As the event is indicated as I for the drivers who are intoxicated, the value of I¯ is for the drivers who are not intoxicated. Its value is calculated as follows
P(I¯)=1-P(I)
P(I¯)=1-0.00589
P(I¯)=0.99411
So the probability of drivers who are not intoxicated is P(I¯) and is given as 0.99411.
