Question

When the author observed a sobriety checkpoint conducted by the Dutchess County Sheriff Department, he saw that 676 drivers were screened and 6 were arrested for dri vi ng while intoxicated. Based on those​ results, we can estimate that P(I) = 0.00589​, where W denotes the event of screening a driver and getting someone who is intoxicated. What does P(I¯) ​denote, and what is its​ value?

Answer 1

Answer:

The probability of drivers who are not intoxicated is P(I¯) and is given as 0.99411.

Step-by-step explanation:

As the event is indicated as I for the drivers who are intoxicated, the value of I¯ is for the drivers who are not intoxicated. Its value is calculated as follows

P(I¯)=1-P(I)

P(I¯)=1-0.00589

P(I¯)=0.99411

So the probability of drivers who are not intoxicated is P(I¯) and is given as 0.99411.