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DaniilM [7]
3 years ago
9

Write the equation of the line perpendicular to y = x+ 5 that passes through the point ( -7,3).

Mathematics
1 answer:
Burka [1]3 years ago
3 0

Answer:

y = - x - 4

Step-by-step explanation:

A line perpendicular to the line:  y = x + 5

must have a slope that is the "opposite of the reciprocal" of the slope of the given line. Then the slope of the perpendicular line must be "-1".

Now that we know the slope of the perpendicular line, we use the point (-7, 3) to complete the equation of the line:

y = -1 x + b

3 = -1 (-7) + b

then we solve for "b":

3 = 7 + b

3 - 7 = b

b = -4

Now we can write the total equation of the perpendicular line in slope-intercept form as:

y = - x - 4

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kolezko [41]

4 × ( x + 4 ) = 3 × ( 3 + 5 )

4 × ( x + 4 ) = 3 × 8

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Type the correct answer in each box. If necessary, use / for the fraction bar(s).
Tom [10]

Given:

The values are a=0.\overline{6},b=0.75.

To find:

The values of ab and \dfrac{a}{b}.

Solution:

We have,

a=0.\overline{6}

a=0.666...                     ...(i)

Multiply both sides by 10.

10a=6.666...                 ...(ii)

Subtracting (i) from (ii), we get

10a-a=6.666...-0.666...

9a=6

a=\dfrac{6}{9}

a=\dfrac{2}{3}

And,

b=0.75

b=\dfrac{75}{100}

b=\dfrac{3}{4}

Now, the product of a and b is:

ab=\dfrac{2}{3}\times \dfrac{3}{4}

ab=\dfrac{1}{2}

The quotient of a and b is:

\dfrac{a}{b}=\dfrac{\dfrac{2}{3}}{\dfrac{3}{4}}

\dfrac{a}{b}=\dfrac{2}{3}\times \dfrac{4}{3}

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Therefore, the required values are ab=\dfrac{1}{2} and \dfrac{a}{b}=\dfrac{8}{9}.

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3 years ago
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