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MatroZZZ [7]
1 year ago
6

Which equations pass through the points (1, 3) and (7 9)?

Mathematics
1 answer:
ddd [48]1 year ago
8 0

Answer:

f(x)=x+2 Passes through

x-y=2 DOES NOT pass through

Step-by-step explanation:

Method- plug in x and see if the y matches the points. (1,3) (7,9)

f(x)=x+2

f(1)=1+2=3

f(7)=7+2=9

Matches!

x-y=2

1-y=2 --> y=-1

Does not match

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Step-by-step explanation:

2x + y < 10

       y < -2x + 10

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Which is the value of the expression (StartFraction (10 Superscript 4 Baseline) (5 squared) Over (10 cubed) (5 cubed)) cubed?
Flura [38]

Answer:

The value to the given expression is 8

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Step-by-step explanation:

Given expression is (StartFraction (10 Superscript 4 Baseline) (5 squared) Over (10 cubed) (5 cubed)) cubed

Given expression can be written as below

\left[\frac{(10^4)(5^2)}{(10^3)(5^3)}\right]^3

To find the value of the given expression:

\left[\frac{(10^4)(5^2)}{(10^3)(5^3)}\right]^3=\frac{((10^4)(5^2))^3}{((10^3)(5^3))^3}

( By using the property ((\frac{a}{b})^m=\frac{a^m}{b^m} )

=\frac{(10^4)^3(5^2)^3}{(10^3)^3(5^3)^3}

( By using the property (ab)^m=a^mb^m )

=\frac{(10^{12})(5^6)}{(10^9)(5^9)}

( By using the property (a^m)^n=a^{mn} )

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( By using the property \frac{1}{a^m}=a^{-m} )

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=\frac{10^3}{5^3} ( By using the property a^{-m}=\frac{1}{a^m} )

=\frac{1000}{125}

=8

Therefore \left[\frac{(10^4)(5^2)}{(10^3)(5^3)}\right]^3=8

Therefore the value to the given expression is 8

3 0
3 years ago
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