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MrRa [10]
3 years ago
15

Find the midpoint of line AB. A(-4,2) B(0,-4)

Mathematics
2 answers:
Blababa [14]3 years ago
6 0
You could solve this mathematically but i mean you could use your eyes.... Its most likely C

;)
Natali [406]3 years ago
5 0
I think it's c because (-2,-1) looks like the middle. Also, the line between it and A, and it and B look the same. Hope this helps!
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0.416 rounded to the nearest thousandth place
IgorC [24]
It's gonna be 0.416 because 6 is in the thousandths place and nothing it next to it
6 0
3 years ago
-11-(-5)
Sonja [21]

Answer:

B.a numerical expression

6 0
1 year ago
Simplify;<br> 26 ⋅ 26^8<br><br> Please also explain how you got the answer.
antoniya [11.8K]

26 ⋅ 26^8

Multiply by adding the exponents:

Raise 26 to the power of 1 to get:

26^1 * 26^8

Now when you multiply the same number raised to different powers, you add the powers together:

26^1 * 26^8 = 26^(8+1) = 26^9

So 26 * 26^8 simplifies is 26^9

6 0
3 years ago
a garden is made up of two squares and a quarter circle. what are the perimeter and area of the garden
FrozenT [24]
The complete question in the attached figure

Part A) find the perimeter
[perimeter of the garden]=[perimeter square 1]+[perimeter a quarter circle]+[perimeter square 2]

[perimeter square 1]=5+5+5-----> 15 ft
[perimeter square 2]=5+5+5-----> 15 ft
[perimeter a quarter circle]=(2*pi*r)/4------> 2*pi*5/4-----> 7.85 ft

[perimeter of the garden]=[15]+[7.85]+[15]-------> 37.85 ft

the answer Part A) is
the perimeter of the garden is 37.85 ft

Part B) Find the area of the garden

[Area of the garden]=[Area square 1]+[Area a quarter circle]+[Area square 2]

[Area square 1]=5*5-----> 25 ft²
[Area square 2]=5*5-----> 25 ft²
[Area a quarter circle]=(pi*r²)/4------> pi*5²/4-----> 19.625 ft²

[Area of the garden]=[25]+[19.625]+[25]-------> 69.625 ft²

the answer Part B) is
the Area of the garden is 69.625 ft²


8 0
3 years ago
Subtract 2x^2-3xy+4y^2 from 3x^2-5xy-6y^2
Diano4ka-milaya [45]

Answer:

-x^{2} +2xy+10y^{2}

Step-by-step explanation:

2x^2-3xy+4y^2-(3x^2-5xy-6y^2)\\2x^2-3xy+4y^2-3x^2+5xy+6y^2\\-x^{2} +2xy+10y^{2}

8 0
3 years ago
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