
There is a theorem in Geometry stating that the square of the tangent segment (ST) is equal to the product of the external secant segment (TR) and the whole secant segment (TQ).
SQ x SQ = TR x TQ
SQ squared = 7 x 30
SQ squared = 210
SQ =
9514 1404 393
Answer:
f^-1(x) = √(6/(9 -x))
Step-by-step explanation:
The inverse function is the solution to ...
x = f(y)
x = 9 -6/y^2
x +6/y^2 = 9 . . . . . add 6/y^2
6/y^2 = 9 -x . . . . . subtract x
6/(9 -x) = y^2 . . . . . multiply by y^2/(9 -x)
y = √(6/(9 -x)) . . . . take the square root
Then the inverse function can be written as ...
f^-1(x) = √(6/(9 -x)) . . . . . . x < 9
Answer:
x=4
Step-by-step explanation:
We are given that the triangles are congruent.
Specifically, the order of the letters gives that the angles ∠DAB and ∠CBA are corresponding parts of the two congruent triangles. Since corresponding parts of congruent triangles are themselves congruent, ∠DAB ≅ ∠CBA. Thus, m∠DAB = m∠CBA.
Given the expressions for the two angles, we can substitute into the equation, and solve for the requested variable.

Answer:
0.008
Step-by-step explanation:
Answer:
Median:19 mean:350.83
Step-by-step explanation: