Answer:
12
Step-by-step explanation:
5^2 + b^2 = 13^2
25 + b^2 = 169
169-25= 144
take the square root of 144
answer: 12
<h2>
The value of A/b is 2.60</h2>
Step-by-step explanation:
We have cosine formula
c² = a² + b² - 2ab cosC
Here
c = B
a = 6
b = 7
C = 60°
Substituting
B² = 6² + 7² - 2 x 6 x 7 cos60
B² = 43
B = 6.56
b = 7 closest integer to B.
Given that A is area of triangle
A=0.5absinC
A = 0.5 x 6 x 7 x sin60 = 18.19
We need to find ![\frac{A}{b}](https://tex.z-dn.net/?f=%5Cfrac%7BA%7D%7Bb%7D)
![\frac{A}{b}=\frac{18.19}{7}=2.60](https://tex.z-dn.net/?f=%5Cfrac%7BA%7D%7Bb%7D%3D%5Cfrac%7B18.19%7D%7B7%7D%3D2.60)
The value of A/b is 2.60
Answer:
Step-by-step explanation:
To solve using completing square, we need to write the equation as x2+3x=17.
The next step is to add a number such that the square can be completed. The number must be equal to (b/2a)^2, so here it will be (3/2)^2 = 9/4
The equation then becomes x2+3x+(9/4)=17+(9/4).
Solving it further will get you the final answer
Answer:
22m
Step-by-step explanation:
Let height of flagpole=h
AB==17 m
(1 degree= 60 minute)
![\angle B=25^{\circ}43'=25+\frac{43}{60}=25.72^{\circ}](https://tex.z-dn.net/?f=%5Cangle%20B%3D25%5E%7B%5Ccirc%7D43%27%3D25%2B%5Cfrac%7B43%7D%7B60%7D%3D25.72%5E%7B%5Ccirc%7D)
We have to find the approximate height of the flagpole.
In triangle CDA,
![\frac{CD}{DA}=tan\theta=\frac{Perpendicular\;side}{Base}](https://tex.z-dn.net/?f=%5Cfrac%7BCD%7D%7BDA%7D%3Dtan%5Ctheta%3D%5Cfrac%7BPerpendicular%5C%3Bside%7D%7BBase%7D)
![h=DA(0.759)](https://tex.z-dn.net/?f=h%3DDA%280.759%29)
In triangle CDB,
![tan 25.72^{\circ}=\frac{CD}{DB}](https://tex.z-dn.net/?f=tan%2025.72%5E%7B%5Ccirc%7D%3D%5Cfrac%7BCD%7D%7BDB%7D)
![0.482=\frac{h}{DA+17}](https://tex.z-dn.net/?f=0.482%3D%5Cfrac%7Bh%7D%7BDA%2B17%7D)
![0.482DA+8.194=h](https://tex.z-dn.net/?f=0.482DA%2B8.194%3Dh)
Substitute the value
![0.482DA+8.194=0.759DA](https://tex.z-dn.net/?f=0.482DA%2B8.194%3D0.759DA)
![8.194=0.759DA-0.482DA](https://tex.z-dn.net/?f=8.194%3D0.759DA-0.482DA)
![8.194=0.277DA](https://tex.z-dn.net/?f=8.194%3D0.277DA)
![DA=\frac{8.194}{0.277}=29.58](https://tex.z-dn.net/?f=DA%3D%5Cfrac%7B8.194%7D%7B0.277%7D%3D29.58)
Substitute the value
![h=29.58 \times 0.759=22.45 m\approx 22m](https://tex.z-dn.net/?f=h%3D29.58%20%5Ctimes%200.759%3D22.45%20m%5Capprox%2022m)
Hence, the height of the flagpole=22 m
Answer:
0
Step-by-step explanation:
(-7 + 3) - (2 - 6)
PEMDAS
Parentheses first
(-4) - (-4)
Subtracting a negative is adding
-4 +4
0