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1 year ago

Estimate the area for the figure below. Assume that each square in the grid is one square inch.

Mathematics

1 answer:

Nutka1998 [239]1 year ago

5 0

we will segment the sqaure in the shape into the following

full square,

0.75

0.5

0.25

full square = 68

0.75 = 18 x 0.75 = 13.5

0.5 = 5 x 0.5 = 2.5

0.25 = 17 x 0.25 = 4.25

to get the area of figure, we will add up the values that we have gotten

so,

Area of the figure = 68 + 13.5 + 2.5 + 4.25

Area of the figure = 88.25 square meter

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the volume of a cone of radius r and height h is given by v=1/3pir^2h. If the radius and height is both increasing at a constant

Tamiku [17]

Answer:

The rate of change of the volume $\frac{dV}{dt}$ when the height is 9 centimeters and the radius is 6 centimeters is $24\pi \:\frac{cm^3}{s}$

Step-by-step explanation:

This is a related rate problem because you know a rate and want to find another rate that is related to it. If 2 variables both vary with respect to time and have a relation between them, we can express the rate of change of one in terms of the other.

From the information given we know:

$\frac{dr}{dt}=\frac{1}{2}\:\frac{cm}{s}$
$\frac{dh}{dt}=\frac{1}{2}\:\frac{cm}{s}$
The volume of a cone of radius r and height h is given by $V=\frac{1}{3} \pi r^2 h$

We want to find the rate of change of the volume $\frac{dV}{dt}$ when the height is 9 centimeters and the radius is 6 centimeters.

Applying implicit differentiation to the formula of the volume of a cone we get

$\frac{dV}{dt}=\frac{1}{3}\pi [r^2\frac{dh}{dt}+2rh\frac{dr}{dt} ]$

Substituting the values we know into the above formula:

$\frac{dV}{dt}=\frac{1}{3}\pi [(6)^2\frac{1}{2}+2(6)(9)\frac{1}{2} ]\\\\\frac{dV}{dt}=\frac{1}{3}\pi[18+54]\\\\\frac{dV}{dt}=\frac{72\pi}{3}=24\pi \:\frac{cm^3}{s}$

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

Step: Solvey=3x+9for y:

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Fiesta28 [93]

Answer:

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