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2 years ago

15

How do you

1 answer:

Mashutka [201]2 years ago

5 0

Use the pythagorean theorem if you cannot directly measure it. a squared plus b squared = c squared

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48/50 - 20/25 please Answer this ASAP please

Anuta_ua [19.1K]

Answer:

0.16

Step-by-step explanation:

4 0

2 years ago

20 points help plz.

Andrews [41]

This area is equal to the sum of a circle with a radius of 5/2 in and a rectangle 5 by 15 in so:

A=πr^2+xy

A=π(2.5)^2+5*15

A=6.25π+75 in^2

A≈94.63 in^2 (to nearest hundredth) so

A≈95 in^2 (to nearest whole square inch)

8 0

2 years ago

Which number line represents the solutions to 1-2x1 = 4?

kaheart [24]

Answer:

Third option: $x = -2$ and $x = 2$

Step-by-step explanation:

Given:

$|-2x|=4$

For a modulus function, if $|f(x)|=a$ , then,

$f(x)=\pm a$

Here, $f(x)=-2x$ , $a=4$

∴ $-2x=\pm 4\\ -2x=-4\textrm{ or } -2x=4\\ x=\frac{-4}{-2}\textrm{ or }x=\frac{4}{-2}\\ x= 2\textrm{ or }x=-2$

Therefore, the third option is the correct answer as the graph has $x$ values as -2 and 2

8 0

2 years ago

Solve sin 0 + 1 = cos20 on the interval 0 ≤ 0 < 2pi. Show work please!

yan [13]

Answer:

$\theta=\frac{\pi}{2},\frac{3\pi}{2}\frac{2\pi}{3}\frac{4\pi}{3}$

Step-by-step explanation:

You need 2 things in order to solve this equation: a trig identity sheet and a unit circle.

You will find when you look on your trig identity sheet that

$cos(2\theta)=1-2sin^2(\theta)$

so we will make that replacement, getting everything in terms of sin:

$sin(\theta)+1=1-2sin^2(\theta)$

Now we will get everything on one side of the equals sign, set it equal to 0, and solve it:

$2sin^2(\theta)+sin(\theta)=0$

We can factor out the sin(theta), since it's common in both terms:

$sin(\theta)(2sin(\theta)+1)=0$

Because of the Zero Product Property, either

$sin(\theta)=0$ or

$2sin(\theta)+1=0$

Look at the unit circle and find which values of theta have a sin ratio of 0 in the interval from 0 to 2pi. They are:

$\theta=\frac{\pi}{2},\frac{3\pi}{2}$

The next equation needs to first be solved for sin(theta):

$2sin(\theta)+1=0$ so

$2sin(\theta)=-1$ and

$sin(\theta)=-\frac{1}{2}$

Go back to your unit circle and find the values of theta where the sin is -1/2 in the interval. They are:

$\theta=\frac{2\pi}{3},\frac{4\pi}{3}$

7 0

2 years ago

Find the value of x. If necessary, write your answer in simplest radical form. 8 x 2

fenix001 [56]

Answer:

8 · 2 or 8x² or 8x2

Step-by-step explanation:

3 0

2 years ago