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sukhopar [10]
1 year ago
8

D(-4,1),A(-2,5,s(-1,4)N(-1,2

Mathematics
1 answer:
murzikaleks [220]1 year ago
5 0

All of the coordinates in the attached screenshot are in the second quadrant.

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Let f be a function defined for t ≥ 0. Then the integral ℒ{f(t)} = [infinity] e−stf(t) dt 0 is said to be the Laplace transform
sveticcg [70]

Answer:

L(f(t)) = 2 \frac{e^{-s} }{s} - \frac{1}{s}

Step-by-step explanation:

let f be a function defined for t ≥ 0

we can write the function f(t) in terms of unit function as follows

f(t) = 2 u,(t) - 1  where

      0≤ t < 1

f(t) = (2 * 0) -1 = -1

when t ≥ 1

f(t) = (2*1 )- 1 = 1

Now the Laplace transform L(F(T)) = 2L( u, (t) ) - L(1)  --------equation 1

this is because L(u,(t)) = \frac{e^{-cs} }{s}

c = 1 hence L(1) = 1/s

back to equation 1

L(f(t)) = 2 \frac{e^{-cs} }{s} -  1/s  laplace transform

also L(u(t) ) = \frac{e^{-s} }{s}

3 0
3 years ago
The length and width of a rectangle is 8 units and 4 units respectively. Find the area of the rectangle.​
Leno4ka [110]

Answer:

32units

Step-by-step Explanation :

Area of rectangle = length × Width

x = 8 × 4

x = 32

4 0
3 years ago
Read 2 more answers
Need help with this question 15 (1 1/5)
lana [24]
15\left(1\dfrac{1}{5}\right)=15\cdot\dfrac{1\cdot5+1}{5}=15\cdot\dfrac{6}{5}\\\\=3\cdot6=\boxed{18}
6 0
4 years ago
An equation is shown below:
kykrilka [37]
Part A) This equation has only one solution.

Part B:
 
4(2x−5)=4

Simplify both sides of the equation.

4(2x−5)=4

Simplify:

4(2x−5)=4

(4)(2x)+(4)(−5)=4(Distribute)

8x+−20=4

8x−20=4

Add 20 to both sides.

8x−20+20=4+20

8x=24

Divide both sides by 8.

8x / 8 = 24 / 8

x=3
 

8 0
4 years ago
Read 2 more answers
Find the component form of -u - v given that u=(-5,6) and v =(7,-3)
sergij07 [2.7K]

Answer: Third option

-u-v =

Step-by-step explanation:

We have the vector u and the vector v. We must perform the operation -u-v.

To perform this operation multiply the vector u by -1 and multiply the vector v by -1.

If u = (-5,6)

So

-1u = (5, -6)

If v = (7, -3)

So

-1v = (-7, 3)

Then the sum of both vectors is done by adding the components of u with the components of v.

-u-v = (5, -6) + (-7,\ 3)\\\\-u-v = (5-7\ ,\ -6 + 3)\\\\-u-v = (-2,\ -3)

7 0
4 years ago
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