Answer: I've been looking all over for this question nobody's answering it for me
Step-by-step explanation:
You do 3/4 times 8 and that equals 6. I hope this helped you :)
Its 32 because you times all of the sides, so 8 times 4 is 32
Answer:
x = 0 .
-20/19 (see below).
Step-by-step explanation:
√(x + 1) + √5x = √(7x + 1)
Squaring both sides:
x + 1 + 5x + 2√(x + 1)√5x = 7x + 1
2√(x + 1)√5x = 7x +1 - 1 - x - 5x = x
Squaring both sides:
4(x + 1)(5x) = x^2
20x^2 + 20x - x^2 = 0
19x^2 + 20x) = 0
x(19x + 20) = 0
x = 0, -20/19.
If we substitute x = 0 into the original equation we get
√(0 + 1) + √5*0 = √(7*0 + 1)
1 = 1 so this is a true solution.
-20/19 :- √(-20/19 + 1) is not real so unless we allow complex square root this is extraneous.
Answer:
The buildings are 171.4 ft far apart.
Step-by-step explanation:
Height of the of the building-1 = 320 ft
Height of the of the building-2 = 200 ft
Angle of depression from building-1 to to the top of building-2 = θ = 55°
In figure attached, ABC
AB = 320 ft - 200 ft = 120 ft
BC = Distance between the buildings
![\theta =\angle ABC = 55^o](https://tex.z-dn.net/?f=%5Ctheta%20%3D%5Cangle%20ABC%20%3D%2055%5Eo)
In ΔABC
![\tan \theta =\frac{AB}{BC}](https://tex.z-dn.net/?f=%5Ctan%20%5Ctheta%20%3D%5Cfrac%7BAB%7D%7BBC%7D)
![\tan 55^o=\frac{120 ft}{BC}](https://tex.z-dn.net/?f=%5Ctan%2055%5Eo%3D%5Cfrac%7B120%20ft%7D%7BBC%7D)
![BC=120 ft\times \tan 55^o](https://tex.z-dn.net/?f=BC%3D120%20ft%5Ctimes%20%5Ctan%2055%5Eo)
![BC=171.4 ft](https://tex.z-dn.net/?f=BC%3D171.4%20ft)
The buildings are 171.4 ft far apart.