Solving a polynomial inequation
Solving the following inequation:
(x - 8) (x + 1) > 0
We are going to find the sign both parts of the multiplication,
(x - 8) and (x + 1), have when
x < - 8
-8 < x < 1
1 < x
Then we know (x - 8) (x + 1) > 0 whenever (x - 8) (x + 1) is positive
We can see in the figure (x - 8) (x + 1) is positive when x < -8 and x > 1
Then
Answer:B
Answer:
a and d = 32
Step-by-step explanation:
since ABC and DEF are similar m<A = m<D so you have the equation
5x + 12 = 8x
subtract 8x from both sides
5x + 12 -8x = 0
subtract 12 from both sides
5x -8x = -12
combine like terms
-3x = -12
devide by -3
x = 4
plug 4 into equation
5(4) + 12 = 8*4
20 + 12 = 32
32 = 32
Answer:
15400
Step-by-step explanation:
Answer:
i think 65 but if not then it is D impossible
Step-by-step explanation:
hope that helps
and that i wasn't to late
