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Klio2033 [76]
3 years ago
11

DG¯¯¯¯¯¯ , EG¯¯¯¯¯ , and FG¯¯¯¯¯ are perpendicular bisectors of the sides of △ABC . DG=5 cm and BD=12 cm.

Mathematics
1 answer:
jonny [76]3 years ago
3 0
Given that <span>DG, EG, and FG are perpendicular bisectors of the sides of △ABC, this means that the point of intersection, G, is the circumcenter of the triangle and hence A</span><span>G, BG, and CG are equal.

Given that </span><span>DG = 5 cm and BD = 12 cm, then

BG= \sqrt{DG^2+BD^2}  \\  \\ = \sqrt{5^2+12^2} = \sqrt{25+144}  \\  \\ = \sqrt{169} =13

Since AG = BG = CG, therefore, CG = 13 cm.</span>
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Step-by-step explanation:

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Find an equation of the line through these points (15,2.2) (5,1.6). Write answer in a slope-intercept form
nadya68 [22]

Answer:

y=\frac{\displaystyle 3}{\displaystyle 50}x+\frac{\displaystyle 13}{\displaystyle 10}

Step-by-step explanation:

Hi there!

Slope-intercept form: y=mx+b where m is the slope and b is the y-intercept (the value of y when x is 0)

<u>1) Determine the slope (</u><u><em>m</em></u><u>)</u>

m=\frac{\displaystyle y_2-y_1}{\displaystyle x_2-x_1} where two given points are (x_1,y_1) and (x_2,y_2)

Plug in the given points (15,2.2) and (5,1.6):

m=\frac{\displaystyle 1.6-2.2}{\displaystyle 5-15}\\\\m=\frac{\displaystyle -0.6}{\displaystyle -10}\\\\m=\frac{\displaystyle 0.6}{\displaystyle 10}\\\\m=\frac{\displaystyle 0.3}{\displaystyle 5}\\\\m=\frac{\displaystyle 3}{\displaystyle 50}

Therefore, the slope of the line is \frac{\displaystyle 3}{\displaystyle 50}. Plug this into y=mx+b:

y=\frac{\displaystyle 3}{\displaystyle 50}x+b

<u>2) Determine the y-intercept (</u><u><em>b</em></u><u>)</u>

y=\frac{\displaystyle 3}{\displaystyle 50}x+b

Plug in a given point and solve for b:

1.6=\frac{\displaystyle 3}{\displaystyle 50}(5)+b\\\\1.6=\frac{\displaystyle 3}{\displaystyle 10}+b\\\\1.6-\frac{\displaystyle 3}{\displaystyle 10}=\frac{\displaystyle 3}{\displaystyle 10}+b-\frac{\displaystyle 3}{\displaystyle 10}\\\\\frac{\displaystyle 13}{\displaystyle 10}=b

Therefore, the y-intercept is \frac{\displaystyle 13}{\displaystyle 10}. Plug this back into y=\frac{\displaystyle 3}{\displaystyle 50}x+b:

y=\frac{\displaystyle 3}{\displaystyle 50}x+\frac{\displaystyle 13}{\displaystyle 10}

I hope this helps!

5 0
3 years ago
Suppose the claim size of an auto collision insurance, X, is uniformly distributed on the interval $1,000 to $10,000. What is th
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35.35%

Step-by-step explanation:

If there were no deductibles, the expected claim payment would be:

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If the collision insurance claim is under $2,000, then the insurer would not pay anything, but if X > $2,000, then the insurer would pay X - $2,000. The new expected value is:

E_2(X)=\frac{2,000-1,000}{10,000-1,000} *0+\frac{10,000-2,000}{10,000-1,000}*\frac{(2,000-2,000)+(10,000-2,000)}{2} \\E_2(X)=\frac{8}{9}*\frac{0+8,000}{2}\\ E_2(X)=\$3,555.56

The percentage reduction on the claim payment is:

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Answer:

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Step-by-step explanation:

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krek1111 [17]

Answer:

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Step-by-step explanation:

Use the distributive property.

2(m + 11)

2 x m = 2m

2 x 11 = 22

Therefore, 2m + 22

3 0
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