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2 years ago

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A dance class consists of 22 students, of which 10 are women and 12 are men. if 5 men and 5 women are to be chosen and then pair

ed o as partners, how many results are possible?

1 answer:

Bad White [126]2 years ago

6 0

2 pairs are possible with this

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muminat

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3 years ago

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3 years ago

26 is whats percent of 40?

faltersainse [42]

100%/x%=40/26
<span>(100/x)*x=(40/26)*x - W</span>e multiply both sides of the equation by x
<span>100=1.53846153846*x - W</span>e divide both sides of the equation by (1.53846153846) to get x
<span>100/1.53846153846=x </span>
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<span>Now we have: </span>
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3 years ago

Write the recurring decimal 0.5 as a fraction in its simplest form.

joja [24]

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3 years ago

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Find the angle between the given vectors to the nearest tenth of a degree.

pochemuha

$\bf \textit{angle between two vectors }\\ \quad \\
cos(\theta)=\cfrac{u \cdot v}{||u||\ ||v||} \implies \cfrac{\text{dot product}}{\text{product of magnitudes}}\\ \quad \\\\
\theta = cos^{-1}\left(\cfrac{u \cdot v}{||u||\ ||v||}\right)\\\\
-----------------------------\\\\
\theta=cos^{-1}\left[ \cfrac{\ \textless \ 8,4\ \textgreater \ \quad \cdot \quad \ \textless \ 9,-9\ \textgreater \ }{(\sqrt{8^2+4^2})(\sqrt{9^2+(-9)^2})} \right]$

$\bf \theta=cos^{-1}\left[ \cfrac{(8\cdot 9)+(4\cdot -9)}{(\sqrt{64+16})(\sqrt{81+81})} \right]\implies \theta=cos^{-1}\left[ \cfrac{36}{(\sqrt{80})(\sqrt{162})} \right]
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\theta=cos^{-1}\left[ \cfrac{36}{(\sqrt{80})(\sqrt{162})} \right]\implies 
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\theta=cos^{-1}\left[ \cfrac{36}{36\sqrt{10}}\right]\implies \theta\approx 71.565^o$

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4 years ago

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