Answer:
(x-3)(x^2-7) = x^3 -3x^2 -7x + 21
just change the sign of the root and put x in front of it, then multiply the factors all together
(x-3)(x-sqr7)(x+sqr7) roots come in conjugate pairs to eliminate irrational coefficients
(x-sqr7)(x+sqr7) = x^2-7. similar to (a-b)(a+b) = a^2-b^2
Step-by-step explanation:
Infinitely many? Arrows indicate that the graph goes on continuously without a stopping point, even in parabolas.
Howdy!
2 shapes that have the exact same size and shape are CONGRUENT.
Have a nice day, Jesus loves you.
You will have approximately $257 at the end of 8 years.
3, if you do the y^2-y^1/x^2-x^1 you will get 3/1 which will be simplified to 3.