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Snezhnost [94]
4 years ago
13

After learning how to fly, wendy reduced her daily commute time by 75%, percent. Previously, her commute took m minutes.

Mathematics
2 answers:
vazorg [7]4 years ago
6 0

Answer:

\frac{1}{4}m

Step-by-step explanation:

suppose m represents 100% of the time it took for wendy to travel

if she reduces her travel time by 75%, to find the amount of time she currently takes we subtract the original time minus the time saved to find the time she is currently traveling

100-75=25

let's assume that 100 is equal to 1 now to find out how much 25 equals we apply a simple rule of three

100 \longrightarrow 1\\25 \longrightarrow x\\x=\frac{25}{100} \\x= \frac{1}{4}

Then 25% of the time (which is what she now takes to travel) is equivalent to 1/4 of the original time it took

then if it took<em> m minutes</em> now it will take  \frac{1}{4} m

Gnesinka [82]4 years ago
3 0

Suppose Wendy has to travel from A to B.

Starting  commute time = m minutes

Wendy started learning  flying i.e other way of commuting

it reduces her commute time by 75%

   A.T.Q

now the new time i.e less time taken by Wendy to commute from A to B=

      = m-75%of m

     =  m- \frac{75\times m}{100}

     =  \frac{25\times m}{100}

     =  m/4 Minutes

So,New commuting time for Wendy = m/4 Minutes


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Answer:

The diameter of the track needs to be 127.27 feet

Step-by-step explanation:

* Lets explain how to solve the problem

- The circumference of any circle is C = 2πr, where r is the radius

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* <u><em>Lets solve the problem</em></u>

- The circumference of the track is 400 feet

∵ The circumference = 2πr

∵ π = 22/7

∴ 400 = 2 × 22/7 × r

∴ 400 = 44/7 r

- Divide both sides by 44/7 to find r

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Step-by-step explanation:

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Answer:

1. P(X>69)=P(Z>-1.136)=1-P(Z

2. P(X

3. P(52.6 \leq X \leq 105.4)=P(-3

Step-by-step explanation:

Assuming the value for the mean 79 and the deviation 8.8

1) Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

2) Part a

Let X the random variable that represent the amount of collagen of a population, and for this case we know the distribution for X is given by:

X \sim N(79,8.8)  

Where \mu=79 and \sigma=8.8

We are interested on this probability

P(X>69)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X>69)=P(\frac{X-\mu}{\sigma}>\frac{69-\mu}{\sigma})=P(Z-1.136)

And we can find this probability on this way:

P(Z>-1.136)=1-P(Z

3) Part b

P(X

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X

And we can find this probability on this way:

P(Z

4) Part c

We need to find first the limits for 3 deviations within the mean

\mu -3 \sigma = 79-3(8.8)=52.6

\mu +3 \sigma = 79+3(8.8)=105.4

P(52.6

And we can find this probability on this way:

P(-3

And in order to find these probabilities we can use tables for the normal standard distribution, excel or a calculator.  

P(-3

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