a.
Critical points occur where 
. The exponential factor is always positive, so we have
b. As the previous answer established, the critical point occurs at (-3, 8) if 
and 
.
c. Check the determinant of the Hessian matrix of 
:
The second-order derivatives are
so that the determinant of the Hessian is
The sign of the determinant is unchanged by the exponential term so we can ignore it. For 
and 
, the remaining factor in the determinant has a value of 4, which is positive. At this point we also have
which is negative, and this indicates that (-3, 8) is a local maximum.
Answer:
5 3/8
Step-by-step explanation:
3 1/8 ÷(x−4 7/28 )= 17/18 +1 5/6
Get a common denominator for the right side
3 1/8 ÷(x−4 7/28 )= 17/18 +1 15/18
Combine like terms
3 1/8 ÷(x−4 7/28 )= 1 32/18
3 1/8 ÷(x−4 7/28 )= 2 14/18
3 1/8 ÷(x−4 7/28 )= 2 7/9
We have a ÷ b = c
Rewriting as a ÷c = b
3 1/8 ÷ 2 7/9 = (x−4 7/28 )
Changing from mixed numbers to improper fractions
25/8 ÷ 25 /9 = (x−4 7/28 )
Copy dot flip
25/8 * 9/25 = (x−4 7/28 )
9/8 = (x−4 7/28 )
Add 4 7/28 to each side
9/8 + 4 7/28 = (x−4 7/28 )+ 4 7/28
Simplifying the fractions
9/8 + 4 1/4 = x
Getting a common denominator
9/8 + 4 2/8 =x
4 11/8 =x
4 + 8/8+3/8 =x
5 3/8
Answer:
Y=2x-1
Step-by-step explanation:
In order to find the slope, its rise over run. So you would move from (0,-1) to the next point it intercepts, (1,1) and find it from there
As for the Y-Intercept, it would just be wherever the line connects with the Y axis, which happens to be (0,-1) or Negative 1.
Answer: Not really sure what you mean by algebra tiles but I do know that x=2.
