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2 years ago

9. Which graph can be used to find the solution to the system of equations?

Mathematics

1 answer:

blsea [12.9K]2 years ago

8 0

I used desmos and plotted the equations in. I would find which graphs cross one another at (-2,-3)

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The equation that passes through (3,6) and is perpendicular to 3x - 4y = - 2

Fynjy0 [20]

Answer:

Step-by-step explanation:

We want the equation of the line that passes through (3, 6) and is perpendicular to:

$3x-4y=-2$

First, convert the second equation into slope-intercept form:

$-4y=-3x-2\Rightarrow \displaystyle y=\frac{3}{4}x+\frac{1}{2}$

So, we can see that the slope of the line is 3/4.

The slopes of perpendicular lines are negative reciprocals of each other.

Therefore, the slope of the new line is -4/3.

It passes through the point (3, 6).

We can use the point-slope form:

$y-y_1=m(x-x_1)$

Substitute:

$\displaystyle y-(6)=-\frac{4}{3}(x-3)$

Distribute:

$\displaystyle y-6=-\frac{4}{3}x+4$

Therefore:

$\displaystyle y=-\frac{4}{3}x+10$

The answer is C.

5 0

2 years ago

Given that p(b|a)=0.75 and p(a)=0.35, what is p(b and a)

Nikitich [7]

Answer:

1.0125

Step-by-step explanation:

Since b/a is 0.75 and a is given as 0.35

Then let's start by solving for b

Ok...how

b/a=0.75

a=0.35

Then make b the subject of formula

b=0.75×a

Then substitute the value of a

b=0.75×0.35

b=0.2625

Let's continue

b and a means b + a

0.75+0.2625

1.0125

Therefore the final answer is 1.0125

6 0

3 years ago

Out of 49 fish 31 are goldfish. About what percent are gold fish?

myrzilka [38]

63.27 % of fishes are gold fish

<h3><u>Solution:</u></h3>

Given that out of 49 fish, 31 are goldfish

To find: percent of gold fish

The percent of gold fish is calculated by dividing number of goldfish by total number of fish multiplied by 100

<em><u>The percentage of gold fish is given by formula:</u></em>

$\text{percent} = \frac{\text{number of gold fish}}{\text{total number of fish}} \times 100$

From given information,

total number of fish = 49

number of gold fish = 31

Substituting the values in formula, we get

$percent = \frac{31}{49} \times 100\\\\percent = 0.6326 \times 100 = 63.27$

Therefore, approximately 63.27 % of fishes are goldfish

4 0

2 years ago

The half-life of iodine-123 is about 13 hours. You begin with 38 grams of iodine-123.

qaws [65]

Half-life, h = 13 hours
Mass initial, a = 38 g
B=base for half-life = 2
(a)
I(t)=a*B^(-t/h)=a*(B^(1/h)^(-t)=a*(B^(-1/13))^t
Substituting values,
I(t)=38*(2^(-1/13))^t
a=38 g
b=2^(-1/13)=0.9480775 (approximately)
=>
I(t)=38*0.9480775^t

(b) I(t)=7
solve
I(t)=7=38*0.948077^t
Take log on both sides and solve for t
t=log(7/38)/log(0.948077)
=31.727 hours.

Check: I(31.727)=38*9.948077^(31.727)=7.000 g ok

7 0

2 years ago

Joey had a large bag of the same amount of blue and orange toy bears. He randomly pulled out a bear and replaced it. The results

boyakko [2]

Answer:

use division for the numbers.

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers