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MrRissso [65]
2 years ago
7

What is 0.9 as a fraction

Mathematics
2 answers:
Vinvika [58]2 years ago
8 0

Using the place value chart, we can see that the decimal 0.9 is nine tenths, so we can write 0.9 as the fraction 9 out of 10 or \frac{9}{10}.

The fraction is in lowest terms.

Therefore, 0.9 can be written as the fraction \frac{9}{10}, which is in lowest terms.

Image is provided.

Allushta [10]2 years ago
3 0

Answer:

9/10

Step-by-step explanation:

You can write 9 as the numerator (top number), and 10 as the denominator (bottom number), and that will be equivalent to 0.9

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Carry out three steps of the Bisection Method for f(x)=3x−x4 as follows: (a) Show that f(x) has a zero in [1,2]. (b) Determine w
ELEN [110]

Answer:

a) There's a zero between [1,2]

b) There's a zero between [1.5,2]

c) There's a zero between  [1.5,1.75].

Step-by-step explanation:

We have f(x)=3^x-x^4

A)We need to show that f(x) has a zero in the interval [1, 2]. We have to see if the function f is continuous with f(1) and f(2).

f(x)=3^x-x^4\\\\f(1)=3^1-(1)^4=3-1=2\\\\f(2)=3^2-(2)^4=9-16=(-7)

We can see that f(1) and f(2) have opposite signs. And f(1)>f(2) and the function is continuous, this means that exists a real number c between the interval [1,2] where f(c)=0.

B)We have to repeat the same steps of A)

For the subinterval [1,1.5]:

f(x)=3^x-x^4\\\\f(1)=3^1-(1)^4=3-1=2\\\\f(1.5)=3^1^.^5-(1.5)^4=5.19-5.06=0.13

f(1) and f(1.5) have the same signs, this means there's no zero in the subinterval [1,1.5].

For the subinterval [1.5,2]:

f(x)=3^x-x^4\\\\f(1.5)=3^1^.^5-(1.5)^4=5.19-5.06=0.13\\\\f(2)=3^2-(2)^4=9-16=(-7)

f(1.5) and f(2) have opposite signs, this means there's a zero between the subinterval [1.5,2].

C)We have to repeat the same steps of A)

For the subinterval [1,1.25]:

f(x)=3^x-x^4\\\\f(1)=3^1-(1)^4=3-1=2\\\\f(1.25)=3^1^.^2^5-(1.25)^4=3.94-2.44=1.5

f(1) and f(1.25) have the same signs, this means there's no zero in the subinterval [1,1.25].

For the subinterval [1.25,1.5]:

f(x)=3^x-x^4\\\\f(1.25)=3^1^.^2^5-(1.25)^4=3.94-2.44=1.5\\\\f(1.5)=3^1^.^5-(1.5)^4=5.19-5.06=0.13

f(1.25) and f(1.5) have the same signs, this means there's no zero in the subinterval [1.25,1.5].

For the subinterval [1.5,1.75]:

f(x)=3^x-x^4\\\\f(1.5)=3^1^.^5-(1.5)^4=5.19-5.06=0.13\\\\f(1.75)=3^1^.^7^5-(1.75)^4=6.83-9.37=(-2.54)

f(1.5) and f(1.75) have opposite signs, this means there's a zero between the subinterval [1.5,1.75].

For the subinterval [1.75,2]:

f(x)=3^x-x^4\\\\f(1.75)=3^1^.^7^5-(1.75)^4=6.83-9.37=(-2.54)\\\\f(2)=3^2-(2)^4=9-16=(-7)

f(1.75) and f(2) have the same signs, this means there isn't a zero between the subinterval [1.75,2].

The graph of the function shows that the answers are correct.

6 0
2 years ago
2/3 x 4/7 write the answer in the simplest form
trapecia [35]

Answer:

8/21

I don't think that it can be simplified further....

6 0
2 years ago
Read 2 more answers
If anyone can help, thanks!
saul85 [17]

Note: This is a perfect application for equations of ratios.


50 40

------- = ------- and so 50x = 1200, or 5x = 120, or x = 24 (miles).

30 x

3 0
3 years ago
If f'(0) = 5 and F(x) = f(3x), what is F'(0)?
Llana [10]

Answer:

\displaystyle F'(0) = 15

Step-by-step explanation:

We are given that:

f'(0) = 5 \text{ and } F(x) = f(3x)

And we want to find F'(0).

First, find F(x):

\displaystyle F'(x) = \frac{d}{dx}\left[ f(3x)]

From the chain rule:

\displaystyle \begin{aligned} F'(x) &= f'(3x) \cdot \frac{d}{dx} \left[ 3x\right] \\ \\ &= 3f'(3x)\end{aligned}

Then:

\displaystyle \begin{aligned} F'(0) & = 3f'(3(0)) \\ \\ & = 3f'(0) \\ \\ & = 3(5) \\ \\ & = 15\end{aligned}

In conclusion, F'(0) = 15.

7 0
2 years ago
Read 2 more answers
30 POINTS!!! Which choice is equivalent to the fraction below when x is greater than or equal to 3?
Mashcka [7]

Answer: C.

\frac{9}{\sqrt{x} -\sqrt{x-3} }=\frac{9(\sqrt{x} +\sqrt{x-3} )}{x-(x-3)}=\frac{9(\sqrt{x} +\sqrt{x-3} )}{3}=3(\sqrt{x} +\sqrt{x-3})

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
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